Question

我遇到了SQL问题。例如，我有链接http://www.site.com/single_video.php?id=96&kategorija=fails

在该页面中有两列，一列用于显示视频，另一列用于相关视频。但是，如果用户添加'链接，它将在列“相关视频”中显示任何内容。所以我试图过滤掉“有效”类别..但不知怎的，它不起作用.. 这是我的代码......

<?php
include 'includes/connect_video_index.php';
mysql_query("SET NAMES utf8"); //recimo bazi da postoje čak i hrvatska slova :D 
$result1 = mysql_query('SELECT * 
                          FROM video 
                         WHERE id!="'.$id1.'" 
                           AND kategorija="'.$escaped_cat.'" 
                      ORDER BY RAND() 
                         LIMIT 10', $con1);
while ($row1 = mysql_fetch_array($result1)){
    $kat = $_GET['kategorija'];
    $kategorija = mysql_real_escape_string($kat);
    if ($kategorija == $row1['kategorija']){
        echo 'This category exists'; //this part is working
    } else {
        //this part doesn't works when I enter blah blah, or whatever :S
        echo "This category doesnt' exist"; 
    }
}

Answer 1

如果键入'somethingThatCantBeFound'，则找不到行，而while循环进行... 0迭代。这意味着您无法访问if语句。如果$escaped_cat和$kategorija相同，我的意思是。是吗？

如果您想知道类别~~是否存在~~有视频，您可以这样做：

SELECT EXISTS (SELECT * FROM video WHERE kategorija = 'some category')

检查类别问题

1 个答案: