我需要解析twitter用户提要,我正在尝试从json字符串创建JSON对象。我能正确地获取json字符串,但是当我尝试从中创建JSON对象时,它显示JSONException
。这是我尝试的代码。
package com.heath_bar.twitter;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.entity.StringEntity;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.params.BasicHttpParams;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.util.Base64;
import android.util.Log;
import android.view.Menu;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.TextView;
public class MainActivity extends Activity {
final String URL = "https://api.twitter.com/1.1/statuses/user_timeline.json?screen_name=*******";
final String APIKEY = "***********************";
final String APISECRET = "*********************";
final String BearerToken = "AAAAAAAAAAAAAAAAAAAAAMRF***************************";
JSONObject jsonObj = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
Button btn_get_feed = (Button) findViewById(R.id.btn_get_feed);
btn_get_feed.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
String bearer_token = BearerToken;
new GetFeedTask().execute(bearer_token, URL);
}
});
}
protected class GetFeedTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... params) {
try {
DefaultHttpClient httpclient = new DefaultHttpClient(
new BasicHttpParams());
HttpGet httpget = new HttpGet(params[1]);
httpget.setHeader("Authorization", "Bearer " + params[0]);
httpget.setHeader("Content-type", "application/json");
InputStream inputStream = null;
HttpResponse response = httpclient.execute(httpget);
HttpEntity entity = response.getEntity();
inputStream = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(
inputStream, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
inputStream.close();
return sb.toString();
} catch (Exception e) {
Log.e("GetFeedTask", "Error:" + e.getMessage());
return null;
}
}
@Override
protected void onPostExecute(String jsonText) {
try {
TextView txt = (TextView) findViewById(R.id.txt_feed);
txt.setText(jsonText); // this is showing the JSON string
try {
jsonObj = new JSONObject(jsonText);
Log.d("status_success", "Successfully created JSON object");
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
} catch (Exception e) {
Log.e("GetFeedTask", "Error:" + e.getMessage());
}
}
}
}
答案 0 :(得分:1)
<强> I need to parse twitter feed.......
强>
尝试使用JSONArray
代替JSONObject
。
JSONArray jsonArray = new JSONArray(jsonText);
Twitter REST API 1.1 Feed以阵列节点开始。可以找到示例twitter JSON Feed here。
[
{
"coordinates": null,
"favorited": false,
"truncated": false,
"created_at": "Wed Aug 29 17:12:58 +0000 2012",
"id_str": "240859602684612608",
"entities": {
"urls": [
{
"expanded_url": "https://dev.twitter.com/blog/twitter-certified-products",
"url": "https://t.co/MjJ8xAnT",
"indices": [
52,
73
],
"display_url": "dev.twitter.com/blog/twitter-c\u2026"
}
],
"hashtags": [
],
"user_mentions": [
]
},
"in_reply_to_user_id_str": null,
"contributors": null,
"text": "Introducing the Twitter Certified Products Program: https://t.co/MjJ8xAnT",
"retweet_count": 121,
"in_reply_to_status_id_str": null,
"id": 240859602684612608,
"geo": null,
"retweeted": false,
"possibly_sensitive": false,
"in_reply_to_user_id": null,
"place": null,
"user": {
"profile_sidebar_fill_color": "DDEEF6",
"profile_sidebar_border_color": "C0DEED",
"profile_background_tile": false,
"name": "Twitter API",
"profile_image_url": "http://a0.twimg.com/profile_images/2284174872/7df3h38zabcvjylnyfe3_normal.png",
"created_at": "Wed May 23 06:01:13 +0000 2007",
"location": "San Francisco, CA",
"follow_request_sent": false,
"profile_link_color": "0084B4",
"is_translator": false,
"id_str": "6253282",
"entities": {
"url": {
"urls": [
{
"expanded_url": null,
"url": "http://dev.twitter.com",
"indices": [
0,
22
]
}
]
},
"description": {
"urls": [
]
}
}
]
答案 1 :(得分:1)
Twitter推文在每个JSONObject的“text”标签下。 从json数组访问每个json对象,如下所示
ArrayList<String> tweets=new ArrayList<String>();
JSONArray array =new JSONArray(jsonText);
for(int i=0;i<array.length();i++){
JSONObject obj=array.getJSONObject(i);
String text=obj.getString("text");
tweets.add(text);
ArrayAdapter<String> adapter=new ArrayAdapter<String>(getBaseContext(),android.R.layout.simple_list_item_1,tweets);
lv.setAdapter(adapter);// displaying in a listview
}