我有人在我的应用上加载一堆图片时出错,但我不确定是什么导致它。
这是他得到的错误。 LINE 135位于底部 我在想他手机上的内存不足。他正在使用2010年制作的Desire HD。这种方法的作用是从服务器获取图像并将其保存在哈希映射中。随着它显示在屏幕上。关于如何防止这个OUTMEMORYERROR的任何想法?
我正在考虑设置一个计数器,如果有超过20张图像,则只清除哈希映射。
logcat的:
java.lang.RuntimeException: An error occured while executing doInBackground()
at android.os.AsyncTask$3.done(AsyncTask.java:200)
at java.util.concurrent.FutureTask$Sync.innerSetException(FutureTask.java:274)
at java.util.concurrent.FutureTask.setException(FutureTask.java:125)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:308)
at java.util.concurrent.FutureTask.run(FutureTask.java:138)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1088)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:581)
at java.lang.Thread.run(Thread.java:1019)
Caused by: java.lang.OutOfMemoryError: bitmap size exceeds VM budget
at android.graphics.BitmapFactory.nativeDecodeStream(Native Method)
at android.graphics.BitmapFactory.decodeStream(BitmapFactory.java:470)
at android.graphics.BitmapFactory.decodeResourceStream(BitmapFactory.java:336)
at android.graphics.drawable.Drawable.createFromResourceStream(Drawable.java:697)
at android.graphics.drawable.Drawable.createFromStream(Drawable.java:657)
at com.codalata.craigslistchecker.GETTHEIMAGE$ITask.doInBackground(GETTHEIMAGE.java:135)
at com.codalata.craigslistchecker.GETTHEIMAGE$ITask.doInBackground(GETTHEIMAGE.java:1)
at android.os.AsyncTask$2.call(AsyncTask.java:185)
at java.util.concurrent.FutureTask$Sync.innerRun(FutureTask.java:306)
代码:
public class GETTHEIMAGE {
private HashMap<String, Drawable> ICache;
private static Drawable DefIcon = null;
private BaseAdapter adapt;
private ItemView item;
private int num = 0;
public GETTHEIMAGE(Context c) {
ICache = new HashMap<String, Drawable>();
}
public Drawable GetTheImagedata(
com.codalata.craigslistchecker.Favorites.TheListAdapter theListAdapter,
ImageView ICON_IMG) {
this.adapt = theListAdapter;
String url = (String) ICON_IMG.getTag();
if (ICache.containsKey(url)) {
return ICache.get(url);
} else {
new ITask().execute(url);
return DefIcon;
}
}
public Drawable GetTheImagedata(TheListAdapter adapter, ImageView ICON_IMG) {
this.adapt = adapter;
String url = (String) ICON_IMG.getTag();
if (ICache.containsKey(url)) {
return ICache.get(url);
} else {
new ITask().execute(url);
return DefIcon;
}
}
public Drawable GetTheImagedata2(ItemView itemView, String string) {
this.item = itemView;
String url = string;
if (ICache.containsKey(url)) {
return ICache.get(url);
} else {
new ITask2().execute(url);
return DefIcon;
}
}
private class ITask2 extends AsyncTask<String, Void, Drawable> {
private String Nick;
@Override
protected Drawable doInBackground(String... params) {
Nick = params[0];
InputStream isImage = null;
try {
URL url = new URL(Nick);
isImage = url.openStream();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return Drawable.createFromStream(isImage, "Nick");
}
@Override
protected void onPostExecute(Drawable result) {
super.onPostExecute(result);
if (num == 0) {
item.ivItemimage1.setImageDrawable(result);
}
if (num == 1) {
item.ivItemimage2.setImageDrawable(result);
}
if (num == 2) {
item.ivItemimage3.setImageDrawable(result);
}
if (num == 3) {
item.ivItemimage4.setImageDrawable(result);
}
if (num == 4) {
item.ivItemimage5.setImageDrawable(result);
}
if (num == 5) {
item.ivItemimage6.setImageDrawable(result);
}
if (num == 6) {
item.ivItemimage7.setImageDrawable(result);
}
if (num == 7) {
item.ivItemimage8.setImageDrawable(result);
}
if (num == 8) {
item.ivItemimage9.setImageDrawable(result);
}
if (num == 9) {
item.ivItemimage10.setImageDrawable(result);
}
num++;
}
}
private class ITask extends AsyncTask<String, Void, Drawable> {
private String Nick;
@Override
protected Drawable doInBackground(String... params) {
Nick = params[0];
InputStream isImage = null;
try {
URL url = new URL(Nick);
isImage = url.openStream();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try{
LINE 135 -----> return Drawable.createFromStream(isImage, "Nick");
}catch(Exception e){
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Drawable result) {
super.onPostExecute(result);
synchronized (this) {
ICache.put(Nick, result);
}
adapt.notifyDataSetChanged();
}
}
}
答案 0 :(得分:1)
您需要缩小位图并在内存中加载缩小版本。
http://developer.android.com/training/displaying-bitmaps/load-bitmap.html
Use appropriateBitmapFactory.decode
method as needed.
这是一个例子:
Out of Memory error with Bitmap
注意:从Android 3.0(API级别11)开始,像素数据与相关位图一起存储在Dalvik堆上。
在Android 2.3.3(API级别10)及更低版本上,建议使用recycle()
。如果您在应用中显示大量位图数据,则可能会遇到OutOfMemoryError错误。 recycle()方法允许应用程序尽快回收内存。
Android 3.0(API Level 11)引入了BitmapFactory.Options.inBitmap
字段。如果设置了此选项,则采用Options对象的解码方法将在加载内容时尝试重用现有位图。这意味着重用了位图的内存,从而提高了性能,并删除了内存分配和取消分配。
http://developer.android.com/training/displaying-bitmaps/manage-memory.html
答案 1 :(得分:0)
num++;
中的总是在增加,所以在某个值上它超出了为这个程序分配的内存空间,你应该为它设置一个控件