一些上下文我问了一个关于MySQL请求的问题,我的帖子可以在那里找到:Need help about joining tables
现在我有另外一个与此相关的问题,所以在我的页面上我列出了我的请求来自数据库的票证:
"SELECT
glpi_tickets.id,
glpi_tickets.name,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 1 THEN
CONCAT(glpi_users.firstname, ' ', glpi_users.realname)
END) AS creator,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 1 THEN
CONCAT(glpi_tickets_users.users_id)
END) AS creator_id,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 2 THEN
CONCAT(glpi_users.firstname, ' ', glpi_users.realname)
END) AS users,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 2 THEN
CONCAT(glpi_tickets_users.users_id)
END) AS users_id,
glpi_tickets.date,
glpi_tickets.priority,
glpi_tickets.date_mod,
glpi_itilcategories.completename,
glpi_tickets.status,
glpi_tickets.users_id_lastupdater,
GROUP_CONCAT(
CASE WHEN glpi_tickets.users_id_lastupdater = glpi_users.id THEN
CONCAT(glpi_users.firstname, ' ', glpi_users.realname)
END SEPARATOR '<br>') AS last_updater,
glpi_tickets.content
FROM
glpi_tickets
JOIN glpi_tickets_users ON glpi_tickets_users.tickets_id = glpi_tickets.id
JOIN glpi_users ON glpi_users.id = glpi_tickets_users.users_id
JOIN glpi_itilcategories ON glpi_itilcategories.id = glpi_tickets.itilcategories_id
GROUP BY
glpi_tickets.id"
结果如下:
[ID][Title][creator][date created][priority][category][status][date modified][assigned to][last update by]
[125][helpdesk test][admin][29-01-2013 21:09][low][messaging][new][30-01-2013 17:52][Tony][admin]
对于每张故障单,creator - creator_id和users - users_id可以包含多个ID和名称。
现在我想在另一个页面中显示用户信息,我使用相同的请求,但WHERE glpi_users.id = ?
获取users.php?id=x
除了创作者和用户之外,一切正常,因为WHERE glpi_users.id = x
只选择一个人。
我希望有一种方式可以像之前的请求一样显示,提前谢谢
编辑:尝试过GolezTrols解决方案,但它不能正常工作,这是我的查询:
"SELECT
glpi_tickets.id,
glpi_tickets.name,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 1 THEN
CONCAT(glpi_users.firstname, ' ', glpi_users.realname)
END) AS creator,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 1 THEN
CONCAT(glpi_tickets_users.users_id)
END) AS creator_id,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 2 THEN
CONCAT(glpi_users.firstname, ' ', glpi_users.realname)
END) AS users,
GROUP_CONCAT(
CASE WHEN glpi_tickets_users.type = 2 THEN
CONCAT(glpi_tickets_users.users_id)
END) AS users_id,
glpi_tickets.date,
glpi_tickets.priority,
glpi_tickets.date_mod,
glpi_itilcategories.completename,
glpi_tickets.status,
glpi_tickets.users_id_lastupdater,
GROUP_CONCAT(
CASE WHEN glpi_tickets.users_id_lastupdater = glpi_users.id THEN
CONCAT(glpi_users.firstname, ' ', glpi_users.realname)
END SEPARATOR '<br>') AS last_updater,
glpi_tickets.content
FROM
glpi_tickets
JOIN glpi_tickets_users ON glpi_tickets_users.tickets_id = glpi_tickets.id
JOIN glpi_users ON glpi_users.id = glpi_tickets_users.users_id
JOIN glpi_itilcategories ON glpi_itilcategories.id = glpi_tickets.itilcategories_id
WHERE
exists (
SELECT
'x'
FROM
glpi_tickets_users
WHERE
glpi_tickets_users.tickets_id = glpi_tickets.id AND
glpi_tickets_users.id = ? AND
glpi_tickets_users.type = 1)
GROUP BY
glpi_tickets.id"
几乎所有时间它都没有显示票证,有时它显示票证但与用户无关,例如,如果我尝试users.php?id=1536
它将显示由用户创建的票号789 870用户1180和1632负责此票......
答案 0 :(得分:1)
您应该检查用户是否与问题相关,而不是对确切的用户ID进行过滤,如下所示:
select
t.title,
group_concat(
case when tu.type = 1 then
concat(u.firstname, ' ', u.lastname)
end) as creator,
t.priority,
t.date,
group_concat(
case when tu.type = 2 then
concat(u.firstname, ' ', u.lastname)
end SEPARATOR ' - ') as users
from
tickets t
inner join tickets_users tu on tu.ticketid = t.id
inner join users u on u.id = tu.userid
where
exists (
select
'x'
from
tickets_users tu2
where
tu2.ticketid = t.id and
tu2.userid = <youruserid> and
tu2.type = 1)
group by
t.id;
对于<youruserid>
,您可以填写所需的用户ID。此查询将返回该用户报告的所有问题(type = 1)。但是对于所有这些问题,仍会返回所有相关用户,因此您的查询结果仍然完整。