Question

这是XML文档：

<?xml version="1.0" encoding="utf-8" ?>
 <ToolBars>
   <ToolBarSet id="1" buttonsCounter="4"  width="252">
      <ToolBarItem id="1" Command="Command11" Icon="pic11" Enabled="true" Visible="true" />
      <ToolBarItem id="2" Command="Command12" Icon="pic12" Enabled="true" Visible="true" />
      <ToolBarItem id="3" Command="Command13" Icon="pic13" Enabled="true" Visible="true" />
      <ToolBarItem id="4" Command="Command14" Icon="pic14" Enabled="false" Visible="true" />      
    </ToolBarSet>
    <ToolBarSet  id="2" buttonsCounter="2"  width="170">
      <ToolBarItem id="1" Command="Command21" Icon="pic11" Enabled="true" Visible="true" />
      <ToolBarItem id="2" Command="Command22" Icon="pic22" Enabled="true" Visible="true" /> 
    </ToolBarSet>
  </ToolBars>

我想填写相应的课程，这是我的代码：
（“公众”只是为了测试）

class Program
    {
        static void Main(string[] args)
        {
            ToolBars test;

            XmlSerializer mySerializer = new XmlSerializer(typeof(ToolBars));
            using (FileStream myFileStream = new FileStream("c:\\XMLFile1.xml", FileMode.Open))
            {

                test = (ToolBars)mySerializer.Deserialize(myFileStream);
            }



        }
    }

    [Serializable]
    [System.Xml.Serialization.XmlRoot("ToolBars")]
    public class ToolBars
    {
        public int id;
        public int buttonsCounter;
        public int width;

        [XmlArray("ToolBarSet")]
        [XmlArrayItem("ToolBar", typeof(Toolbar))]
        public List<Toolbar> toolbars = new List<Toolbar>();             

    }

    [Serializable]
    public class Toolbar
    {      
        [XmlArray("ToolbarItem")]
        [XmlArrayItem("ToolbarItem", typeof(ToolbarItem))]
        public List<ToolbarItem> toolbarItems = new List<ToolbarItem>();

    }

    [Serializable]
    public class ToolbarItem
    {
        public string command;

        public int id;

        public string icon;

        public bool visible;

        public bool enabled;

    }

如何让它发挥作用？

Answer 1

在这种情况下你总是做的是

获取XML文件并在命令行中通过xsd.exe运行它 - ＆gt;这为您提供了XSD架构文件
获取新创建的XSD文件，并使用xsd.exe参数{ - 1}}通过/c运行该文件。这将为您提供一个C＃文件（如果您想要VB.NET，还可以使用/ l：VB），它将能够反序列化您的XML

只要你在两次运行xsd.exe期间没有遇到任何致命错误，你应该好好去，并且应该能够在一秒钟内将任何XML反序列化为C＃对象。

马克

Answer 2

只需用以下内容替换您的类：

[XmlRoot("ToobBars")]
public class ToolBars : List<ToolbarSet>
{

}

public class ToolbarSet
{
    [XmlAttribute]
    public int id { get; set; }
    [XmlAttribute]
    public int buttonsCounter { get; set; }
    [XmlAttribute]
    public int width { get; set; }

    public List<ToolbarItem> ToolBarItems = new List<ToolbarItem>();
}

public class ToolbarItem
{
    [XmlAttribute]
    public string command { get; set; }
    [XmlAttribute]
    public int id { get; set; }
    [XmlAttribute]
    public string icon { get; set; }
    [XmlAttribute]
    public bool visible { get; set; }
    [XmlAttribute]
    public bool enabled { get; set; }
}

Answer 3

您可以使用以下XML格式：

<?xml version="1.0" encoding="utf-8" ?>
<ToolBarConfiguration>
  <ToolBars>
    <ToolBarSet id="1" buttonsCounter="4" width="252">
      <ToolBarItems>
        <ToolBarItem 
          id="1" 
          Command="Command11" Icon="pic11" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="2" 
          Command="Command12" Icon="pic12" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="3" 
          Command="Command13" Icon="pic13" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="4" 
          Command="Command14" Icon="pic14" Enabled="false" Visible="true"/>
      </ToolBarItems>
    </ToolBarSet>
    <ToolBarSet id="2" buttonsCounter="2"  width="170">
      <ToolBarItems>
        <ToolBarItem 
          id="1" 
          Command="Command21" Icon="pic11" Enabled="true" Visible="true"/>
        <ToolBarItem 
          id="2" 
          Command="Command22" Icon="pic22" Enabled="true" Visible="true"/>
      </ToolBarItems>
    </ToolBarSet>
  </ToolBars>
</ToolBarConfiguration>

这些课程：

[Serializable]
[XmlRoot("ToolBarConfiguration")]
public class ToolBars
{
    [XmlArray("ToolBars")]
    [XmlArrayItem("ToolBarSet", typeof(Toolbar))]
    public List<Toolbar> toolbars = new List<Toolbar>();
}

[Serializable]
public class Toolbar
{
    [XmlAttribute("id")]public int id;
    [XmlAttribute("buttonsCounter")]public int buttonsCounter;
    [XmlAttribute("width")]public int width;

    [XmlArray("ToolBarItems")]
    [XmlArrayItem("ToolBarItem", typeof(ToolbarItem))]
    public List<ToolbarItem> toolbarItems = new List<ToolbarItem>();
}

[Serializable]
public class ToolbarItem
{
    [XmlAttribute("Command")]public string command;
    [XmlAttribute("id")]public int id;
    [XmlAttribute("Icon")]public string icon;
    [XmlAttribute("Visible")]public bool visible;
    [XmlAttribute("Enabled")]public bool enabled;
}

修改在你的问题中你也说：

（“公众”只是为了测试）

请注意，对于XML序列化，只会序列化对象的公共属性和字段。

XML反序列化对象组

3 个答案: