我有数据
x=[14.0716101600000 17.7292101600000 21.3868101600000 21.3868101600000 25.0444101600000 28.7020101600000 32.3596101600000 36.0172101600000 39.6748101600000 43.3324101600000 46.9900101600000 50.6476101600000 54.3052101600000 57.9628101600000 61.6204101600000 65.2780101600000 68.9356101600000 72.5932101600000 76.2508101600000 79.9084101600000 83.5660101600000 87.2236101600000]
y=[0 0 0 0.152400000000000 0.152400000000000 0.533400000000000 0.685800000000000 0.838200000000000 0.990600000000000 1.14300000000000 1.14300000000000 1.14300000000000 1.29540000000000 1.44780000000000 1.60020000000000 1.75260000000000 1.90500000000000 2.05740000000000 2.20980000000000 2.36220000000000 2.51460000000000 2.66700000000000]
new_x=[21.38,25.03,28.70,32.33,35.99,39.55,45.13,48.80,54.38,58.05];
然而,当我使用interp1
之类的
new_y = interp1(x,y,new_x);
它没有用。请告诉我原因。非常感谢你!
答案 0 :(得分:2)
x
向量必须严格单调。在您的数据中,x
的第三和第四个元素是相等的。如果您从x
和y
移除
x(4)=[];
y(4)=[];
它没有问题。