Question

当涉及到php和服务器端脚本时，我很新，所以请光临我。我有一个处理文件来验证并通过电子邮件从我的网站发送联系表格。就发送数据而言，一切都运行良好，但它没有正确处理任何错误。现在，如果必填字段为空，则不应允许发送消息。但就像现在一样，它仍然发送消息。我不知道如何解决这个问题所以任何帮助表示赞赏。

这是我的php

    <?php 
if(($_SERVER['REQUEST_METHOD'] =='POST') && (!empty ($_POST['action']))):

if (isset ($_POST['myname'])){$myname=$_POST['myname'];}
if (isset ($_POST['myphone'])){$myphone=$_POST['myphone'];}
if (isset ($_POST['myemail'])){$myemail=$_POST['myemail'];}
if (isset ($_POST['job'])){$job=$_POST['job'];}
if (isset ($_POST['comments'])){
    $comments= filter_var($_POST['comments'], FILTER_SANITIZE_STRING);}

$formerrors = false;



      if($myname === '') :
      $err_myname = '<div class="error"> Sorry, your name is rquired</div>';
      endif;    

      if($myphone === ''):
      $err_myphone = '<div class="error"> Sorry, your phone number is rquired</div>';
      endif;    

      if($myemail === ''):
      $err_myemaile =  '<div class="error"> Sorry, your email is rquired</div>';
      endif;    

      if($job === ''):
      $err_job =  '<div class="error"> Sorry, your business is rquired</div>';
      endif;    



if (!($formerrors)) :
$to = "email@email.com";
$subject = " Request from $myname";

$message = "A new show and tell request from:\n
            $myname \n
            $myemail\n
            $myphone\n
            $job\n
            $comments\n";
$replyto = "From: $myemail";


if(mail($to, $subject, $message)):
    $msg ="Thanks for filling out our form";
    else:
    $msg = "There was a problem sending the message";
    endif; //mail data

endif; //check errors

endif; //form submitted

?>

如果我需要发布更多信息，例如实际的html，请告诉我。

Answer 1

您遇到错误时未设置$formerrors=true，因此始终将其设置为false并始终发送邮件。

尝试这样的事情：

if($myname === '') :
  $err_myname = '<div class="error"> Sorry, your name is rquired</div>';
  $formerrors=true;
endif;

即使有错误，PHP进程也会形成

1 个答案: