AutoCompleteTextView不显示下拉列表,收到警告

时间:2013-07-19 11:51:44

标签: android autocompletetextview

我有一个 ArrayList,其中包含60-70个元素。我将适配器设置为AutoCompleteTextView,如下所示。

AutoCompleteTextView  mRecipient = (AutoCompleteTextView) this.findViewById(R.id.recipient);
        mRecipient.setThreshold(1);
        Log.i("Array list", ""+names);// Here I got the arrayList
        ArrayAdapter<String> nameadapter=new ArrayAdapter<String>(MyClass.this, android.R.layout.simple_list_item_1, names);
        mRecipient.setAdapter(nameadapter);

但是下拉列表没有出现,我在Logcat中得到了一些警告(非错误)。

04-21 17:15:53.017: W/Filter(15093): An exception occured during performFiltering()!
04-21 17:15:53.017: W/Filter(15093): java.lang.NullPointerException
04-21 17:15:53.017: W/Filter(15093):    at android.widget.ArrayAdapter$ArrayFilter.performFiltering(ArrayAdapter.java:437)
04-21 17:15:53.017: W/Filter(15093):    at android.widget.Filter$RequestHandler.handleMessage(Filter.java:234)
04-21 17:15:53.017: W/Filter(15093):    at android.os.Handler.dispatchMessage(Handler.java:99)
04-21 17:15:53.017: W/Filter(15093):    at android.os.Looper.loop(Looper.java:123)
04-21 17:15:53.017: W/Filter(15093):    at android.os.HandlerThread.run(HandlerThread.java:60)

此外我还有一个ListView,现在是空的。

有人可以弄清楚这个警告意味着什么吗?

1 个答案:

答案 0 :(得分:4)

警告来自ArrayAdapter.performFiltering(CharSequence)中的以下代码段:

 String prefixString = prefix.toString().toLowerCase();  // entered by user
 final ArrayList<T> values = mOriginalValues;
 final int count = values.size();
 final ArrayList<T> newValues = new ArrayList<T>(count); // this will be returned
 for (int i = 0; i < count; i++) {
     final T value = values.get(i);                      // in your case, 'value' is null at times
     final String valueText = value.toString().toLowerCase();  // the warning

     // First match against the whole, non-splitted value
     if (valueText.startsWith(prefixString)) {
         newValues.add(value);
     } else {
         final String[] words = valueText.split(" ");
         final int wordCount = words.length;
         for (int k = 0; k < wordCount; k++) {
             if (words[k].startsWith(prefixString)) {
                 newValues.add(value);
                 break;
             }
         }
     }
 }

因此,请检查null中的names值。