我有以下查询:
select *
from cars
where make in ('BMW', 'Toyota', 'Nissan')
我想要做的是将where参数存储在SQL变量中。
类似的东西:
declare @caroptions varchar(max);
select @caroptions = select distinct(make) from carsforsale;
print @caroptions;
select * from cars where make in (@caroptions)
问题是@caroptions
的打印只返回最后一个结果:
select distinct(make) from carsforsale;
我希望它存储多个值。
有什么想法吗?
答案 0 :(得分:8)
您可以使用表变量:
declare @caroptions table
(
car varchar(1000)
)
insert into @caroptions values ('BMW')
insert into @caroptions values ('Toyota')
insert into @caroptions values ('Nissan')
select * from cars where make in (select car from @caroptions)
答案 1 :(得分:4)
如果您想详细查看,请写下这个here。与此同时,你无法完全按照自己的想法去做。
您的选择是:
使用LIKE命令:
DECLARE @CarOptions varchar(100)
SET @CarOptions = 'Ford, Nisan, Toyota'
SELECT *
FROM Cars
WHERE ','+@CarOptions+',' LIKE ',%'+CAST(Make AS varchar)+',%'
分离器功能
DECLARE @CarOptions varchar(100)
SET @CarOptions = 'Ford, Nisan, Toyota'
SELECT Cars.*
FROM Cars
JOIN DelimitedSplit8K (@CarOptions,',') SplitString
ON Cars.Make = SplitString.Item
Dyanmic SQL
DECLARE @CarOptions varchar(100)
SET @CarOptions = 'Ford, Nisan, Toyota'
DECLARE @sql nvarchar(1000)
SET @sql = 'SELECT * ' +
'FROM Cars ' +
'WHERE Make IN ('+@CarOptions+') '
EXEC sp_executesql @sql
与此同时,您最好的选择是完全摆脱变量。
SELECT * FROM cars WHERE make IN (SELECT make FROM carsforsale );
答案 2 :(得分:1)
为什么不呢?
SELECT * FROM cars WHERE make IN (SELECT DISTINCT(make) FROM carsforsale)
答案 3 :(得分:1)
Fetch 1 value in table and store in variable
=======================================================================================
Declare @query int
select @query = p.ProductID From Product p inner join ReOrdering as r on
p.ProductID = r.ProductID and r.MinQty >= p.Qty_Available
print @query
答案 4 :(得分:1)
使用CTE将多个值存储到单个变量中。
;WITH DATA1 AS
(
select car_name
from cars
where make in ('BMW', 'Toyota', 'Nissan')
)
SELECT @car_name = CONCAT(@car_name,',',car_name)
FROM DATA1
select @car_name
答案 5 :(得分:0)
你可以使用JOIN语句。
SELECT distinct c.*
FROM cars c
JOIN carsfrosale s
ON s.id = c.fk_s
如果您想过滤carsforsale列表,可以添加
WHERE s.id in (....)
答案 6 :(得分:0)
在 TSQL 中你可以这样使用 STRING_AGG
select STRING_AGG(car_name,',') as csv
from cars
where make in ('BMW', 'Toyota', 'Nissan')