Question

我有一个多项目构建。构建中的一些项目产生测试结果。一个项目生成一个安装程序，我希望该项目的工件包含来自所有其他项目的测试结果。我尝试这样做（在生成安装程序的项目中）：

// Empty test task, so that we can make the gathering of test results here depend on the tests' having
// been run in other projects in the build
task test << {
}

def dependentTestResultsDir = new File( buildDir, 'dependentTestResults' )

task gatherDependentTestResults( type: Zip, dependsOn: test ) {

    project.parent.subprojects.each { subproject ->

        // Find projects in this build which have a testResults configuration
        if( subproject.configurations.find { it.name == 'testResults' } ) {

            // Extract the test results (which are in a zip file) into a directory
            def tmpDir = new File( dependentTestResultsDir, subproject.name )
            subproject.copy {
                from zipTree( subproject.configurations['testResults'].artifacts.files.singleFile )
                into tmpDir
            }
        }
    }

    // Define the output of this task as the contents of that tree
    from dependentTestResultsDir
}

问题在于，在配置此任务时，其他项目中的测试任务尚未运行，因此它们的工件不存在，我在构建期间收到的消息如下：

The specified zip file ZIP 'C:\[path to project]\build\distributions\[artifact].zip' does not exist and will be silently ignored. This behaviour has been deprecated and is scheduled to be removed in Gradle 2.0

所以我需要做一些事情，这将涉及我的任务的配置被延迟，直到实际生成测试工件。实现这一目标的惯用方法是什么？

我似乎需要经常就Gradle解决这种性质的问题。我想我在概念上遗漏了一些东西。

Answer 1

在这种情况下，你应该能够通过添加<<来使其成为一种行动，如

task gatherDependentTestResults( type: Zip, dependsOn: test ) << {
    // your task code here
}

在Gradle构建生命周期的后期配置任务

1 个答案: