我正在使用带录音机和播放器的应用程序。我正在使用mediaplayer播放录制的.wav文件,同时我想更新到搜索栏。一切都工作正常但我的问题是媒体播放器进度更新到搜索栏没有顺利发生,如果我们是playig一个小文件,搜索栏的拇指在几秒钟或之间跳跃。
任何人都可以帮助我解决方法,使其顺利寻求seekbar的进展。我的代码如下所示。我完全被困在这里。
mediaPlayerIntiate();
mediaPlayerSetSource();
mMediaPlayer.start();
task = new TimerTask() {
@Override
public void run() {
Graphbar.post(new Runnable() {
@Override
public void run() {
if (mMediaPlayer != null) {
if (playButtonState == MediaMode.PLAY) {
if (mMediaPlayer.isPlaying()) {
Graphbar.setProgress(mMediaPlayer
.getCurrentPosition());
mediaPlayerUpdateTimer(mMediaPlayer
.getCurrentPosition());
enableRewindandForward();
}
}
}
}
});
}
};
timer = new Timer();
timer.schedule(task, 0, 8);
答案 0 :(得分:19)
mMediaPlayer.getCurrentPosition()以毫秒为单位返回当前时间,并将此更新为Seekbar,最大容量为100.将一个公式设置为文件长度为100.尝试此函数
MediaPlayer mMediaPlayer = new MediaPlayer();
final SeekBar mSeelBar = new SeekBar(this);
final int duration = mMediaPlayer.getDuration();
final int amoungToupdate = duration / 100;
Timer mTimer = new Timer();
mTimer.schedule(new TimerTask() {
@Override
public void run() {
runOnUiThread(new Runnable() {
@Override
public void run() {
if (!(amoungToupdate * mSeelBar.getProgress() >= duration)) {
int p = mSeelBar.getProgress();
p += 1;
mSeelBar.setProgress(p);
}
}
});
};
}, amoungToupdate);
当媒体播放器开始播放时应该调用此过程。内部
mediaPlayer.setOnPreparedListener(new OnPreparedListener(){
@Override
public void onPrepared(MediaPlayer mp) {
**// call here**
});
<强>更新强>
在几秒钟内更新125次不是你应该做的事情。请增加更新SeekBar的间隔。我在阅读NullPointer的评论后添加了这个
答案 1 :(得分:4)
以下是我处理搜索栏的方式;
mediaPlayer.setOnPreparedListener(new OnPreparedListener(){
@Override
public void onPrepared(MediaPlayer mp) {
mediaPlayer.start();
new SeekBarHandler().execute();
});
现在我有一个名为SeekBarHandler的异步任务,它可以像这样处理搜索栏:
public class SeekBarHandler extends AsyncTask<Void, Void, Void> {
@Override
protected void onPostExecute(Void result) {
Log.d("##########Seek Bar Handler ################","###################Destroyed##################");
super.onPostExecute(result);
}
@Override
protected void onProgressUpdate(Void... values) {
seekBar.setProgress(mediaPlayer.getCurrentPosition());
super.onProgressUpdate(values);
}
@Override
protected Void doInBackground(Void... arg0) {
while(mediaPlayer.isPlaying()&&isViewOn==true) {
try {
Thread.sleep(200);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
onProgressUpdate();
}
return null;
}
}
现在在我的onPause中,我终止了AsyncTask,因为当用户无法看到搜索栏时保持线程运行没有意义
protected void onPause() {
isViewOn=false;
super.onPause();
}
在onResume上,我就像这样启动AsyncTaskAgain
protected void onResume() {
isViewOn=true;
new SeekBarHandler().execute();
super.onResume();
}
正如您所看到的,我使用布尔标志isViewOn来检查视图是否打开以处理搜索条。
答案 2 :(得分:4)
player.prepare(); // or start()
ScheduledExecutorService service = Executors.newScheduledThreadPool(1);
service.scheduleWithFixedDelay(new Runnable()
{
@Override
public void run()
{
progressBar.setProgress(player.getCurrentPosition());
}
}, 1, 1, TimeUnit.MICROSECONDS);
答案 3 :(得分:3)
seekbar.setProgress()只接受int。因此,我们大多数人倾向于将经过的百分比传递给此方法。但是,如果您需要更平滑的进展,那么您可以使用持续时间(以毫秒为单位)作为MAX。然后我们每毫秒更新一次搜索条的进度。下面是一个例子,我每隔15毫秒就更新一次,因为几乎每款Android手机的刷新率都是60 fps(每秒帧数)。
try{
mediaPlayer.start();
seekbar.setProgress(0);
seekbar.setMax(mediaPlayer.getDuration());
// Updating progress bar
seekHandler.postDelayed(updateSeekBar, 15);
} catch (IllegalArgumentException e) {
e.printStackTrace();
} catch (IllegalStateException e) {
e.printStackTrace();
}
/**
* Background Runnable thread
* */
private Runnable updateSeekBar = new Runnable() {
public void run() {
long totalDuration = mediaPlayer.getDuration();
long currentDuration = mediaPlayer.getCurrentPosition();
// Displaying Total Duration time
remaining.setText(""+ milliSecondsToTimer(totalDuration-currentDuration));
// Displaying time completed playing
elapsed.setText(""+ milliSecondsToTimer(currentDuration));
// Updating progress bar
seekbar.setProgress((int)currentDuration);
// Call this thread again after 15 milliseconds => ~ 1000/60fps
seekHandler.postDelayed(this, 15);
}
};
/**
* Function to convert milliseconds time to
* Timer Format
* Hours:Minutes:Seconds
* */
public String milliSecondsToTimer(long milliseconds){
String finalTimerString = "";
String secondsString = "";
// Convert total duration into time
int hours = (int)( milliseconds / (1000*60*60));
int minutes = (int)(milliseconds % (1000*60*60)) / (1000*60);
int seconds = (int) ((milliseconds % (1000*60*60)) % (1000*60) / 1000);
// Add hours if there
if(hours > 0){
finalTimerString = hours + ":";
}
// Prepending 0 to seconds if it is one digit
if(seconds < 10) {
secondsString = "0" + seconds;
}else {
secondsString = "" + seconds;
}
finalTimerString = finalTimerString + minutes + ":" + secondsString;
// return timer string
return finalTimerString;
}
答案 4 :(得分:0)
您遇到的问题与Android的SeekBar的设计/实现方式有关。虽然它运行良好,但您受限于所使用的段的组合(即seekbar.setMax(int)
)和处理程序的延迟时间。
话虽如此,我将SeekBar子类化为使用ViewPropertyAnimators而不是Handler创建我自己的SmoothSeekBar。
答案 5 :(得分:0)
private void startPlaying() {
mediaPlayer = new MediaPlayer();
try {
mediaPlayer.reset();
mediaPlayer.setDataSource(audioPlayerName);
mediaPlayer.prepare();
mediaPlayer.start();
setAudioProgress(); //call method
} catch (Exception e) {
e.printStackTrace();
}
}
public void setAudioProgress() {
total_duration = mediaPlayer.getDuration();
binding.total.setText(timeConversion((long) total_duration));
binding.current.setText(timeConversion((long) current_pos));
binding.seekbar.setMax((int) total_duration);
runnable = new Runnable() {
@Override
public void run() {
try {
current_pos = mediaPlayer.getCurrentPosition();
binding.current.setText(timeConversion((long) current_pos));
binding.seekbar.setProgress((int) current_pos);
handlerProgressBar.postDelayed(this, 1000);
Log.e(LOG_TAG, "11111");
} catch (IllegalStateException ed) {
ed.printStackTrace();
}
}
};
handlerProgressBar.postDelayed(runnable, 1000);
}