Question

我正在编写一个带字符串的函数，必须用从表中取出的两个数字字符替换任何非数字字符。这是我用来探索字符串并找到非数字字符的代码：

SET @string = '1a2b3c4d'
SET @wcount= 0
SET @index = 1
SET @len= LEN(@string)

WHILE @index<= @len
 BEGIN
    SET @char = SUBSTRING(@string, @index, 1)
    IF @char LIKE '%[a-z]%'
      PRINT 'char ' + CONVERT(varchar(10), @index)
    ELSE
      PRINT @char
    SET @index= @index+ 1
 END

输出如下

1
char 2
2
char 4
3
char 6
4
char 8

现在，当我找到一个非数字字符时，我必须将它替换为两个从select中取出的数字字符。 E.g。

SELECT @temp = REPLACEMENT FROM Conversion_Tab WHERE EXPR = @char

总之，如果我有以下字符串'1a2a3a4a'并且'a'的替换为'88'，则结果字符串应为'188288388488'

提前感谢您的帮助。

再见！

Answer 1

试试这个

DECLARE @string VARCHAR(100)
DECLARE @outstring VARCHAR(100)
DECLARE @wcount INT
DECLARE @temp INT
DECLARE @index INT
DECLARE @len INT
DECLARE @char CHAR

SET @string = '1a2a3a4a'
SET @wcount= 0
SET @index = 1
SET @len= LEN(@string)

SET @outstring = ''

WHILE @index<= @len
 BEGIN
    SET @char = SUBSTRING(@string, @index, 1)
    IF @char LIKE '%[a-z]%'
    BEGIN
      SELECT @temp = REPLACEMENT FROM #Conversion_Tab WHERE EXPR = @char
      SET @outstring = @outstring + CONVERT(VARCHAR(10),@temp)
     END
    ELSE
    BEGIN
      SET @outstring = @outstring + @char 
    END
    SET @index= @index+ 1

END

SELECT @outstring

SQL FIDDLE DEMO

Answer 2

看起来你需要isnumeric（）。所以如果不是isnumeric（char）用你的查找值替换它。

取自另一个答案但产生相同的结果

DECLARE @string VARCHAR(100)
DECLARE @outstring VARCHAR(100)
DECLARE @wcount INT
DECLARE @temp INT
DECLARE @index INT
DECLARE @len INT
DECLARE @char CHAR

SET @string = '1a2a3a4a'
SET @wcount= 0
SET @index = 1
SET @len= LEN(@string)

SET @outstring = ''

WHILE @index<= @len
 BEGIN
    SET @char = SUBSTRING(@string, @index, 1)
    IF ISNUMERIC(@char) = 0
    BEGIN
      SELECT @temp = REPLACEMENT FROM #Conversion_Tab WHERE EXPR = @char
      SET @outstring = @outstring + CONVERT(VARCHAR(10),@temp)
     END
    ELSE
    BEGIN
      SET @outstring = @outstring + @char 
    END
    SET @index= @index+ 1

END

SQL - 替换字符串中的非数字字符

2 个答案: