Question

我有一个标准对象，其中我将每个属性转换为func，如果它的值不为null。

public class TestClassCriteria
{
    public bool? ColumnA { get; set; }
    public bool? ColumnB { get; set; }
}

这是我到目前为止所做的，但我很确定我没有正确定义lambda。这就是我想要实现的目标。 funcs.Add(x => x.ColumnA == criteria.ColumnA)。

var properties = criteria.GetType().GetProperties();
var funcs = new List<Func<dynamic, bool>>();

foreach (var property in properties)
{
    var propertyName = property.Name;

    funcs.Add(x => x.GetType().GetProperty(propertyName).Name == criteria.GetType().GetProperty(propertyName).Name);
}

它没有崩溃或导致任何错误，它只是无法正常工作。

非常感谢您提供的任何帮助。

Answer 1

你想要这样的东西吗？

    static List<Func<TEntity, TCriteria, bool>> GetCriteriaFunctions<TEntity, TCriteria>()
    {
        var criteriaFunctions = new List<Func<TEntity, TCriteria, bool>>();

        // searching for nullable properties of criteria
        var criteriaProperties = typeof(TCriteria)
            .GetProperties()
            .Where(p => p.PropertyType.IsGenericType && p.PropertyType.GetGenericTypeDefinition() == typeof(Nullable<>));

        foreach (var property in criteriaProperties)
        {
            // this is entity parameter
            var entityParameterExpression = Expression.Parameter(typeof(TEntity));
            // this is criteria parameter
            var criteriaParameterExpression = Expression.Parameter(typeof(TCriteria));
            // this is criteria property access: "criteria.SomeProperty"
            var criteriaPropertyExpression = Expression.Property(criteriaParameterExpression, property);
            // this is testing for equality between criteria property and entity property;
            // note, that criteria property should be converted first;
            // also, this code makes assumption, that entity and criteria properties have the same names
            var testingForEqualityExpression = Expression.Equal(
                Expression.Convert(criteriaPropertyExpression, property.PropertyType.GetGenericArguments()[0]), 
                Expression.Property(entityParameterExpression, property.Name));

            // criteria.SomeProperty == null ? true : ((EntityPropertyType)criteria.SomeProperty == entity.SomeProperty)
            var body = Expression.Condition(
                Expression.Equal(criteriaPropertyExpression, Expression.Constant(null)), 
                Expression.Constant(true),
                testingForEqualityExpression);

            // let's compile lambda to method
            var criteriaFunction = Expression.Lambda<Func<TEntity, TCriteria, bool>>(body, entityParameterExpression, criteriaParameterExpression).Compile();

            criteriaFunctions.Add(criteriaFunction);
        }

        return criteriaFunctions;
    }

样本实体和样本标准：

class CustomerCriteria
{
    public int? Age { get; set; }
    public bool? IsNew { get; set; }
}

class Customer
{
    public string Name { get; set; }
    public int Age { get; set; }
    public bool IsNew { get; set; }
}

用法：

        var criteriaFunctions = GetCriteriaFunctions<Customer, CustomerCriteria>();
        var customer1 = new Customer { Name = "John", Age = 35, IsNew = false };
        var customer2 = new Customer { Name = "Mary", Age = 27, IsNew = true };
        var criteria1 = new CustomerCriteria { Age = 35 };
        var criteria2 = new CustomerCriteria { IsNew = true };

        Console.WriteLine("Is match: {0}", criteriaFunctions.All(f => f(customer1, criteria1)));
        Console.WriteLine("Is match: {0}", criteriaFunctions.All(f => f(customer2, criteria1)));
        Console.WriteLine("Is match: {0}", criteriaFunctions.All(f => f(customer1, criteria2)));
        Console.WriteLine("Is match: {0}", criteriaFunctions.All(f => f(customer2, criteria2)));

此代码使用强类型成员访问，而不是动态代码，因此，您可以缓存每对的标准列表＆＃34;实体 - 标准＆＃34;和测试实例形成匹配更快。

Answer 2

您当前的表达式正在比较属性名称，但我认为您希望比较属性值：

var funcs = new List<Func<dynamic, bool>>();

foreach (var property in criteria.GetType().GetProperties())
{
    funcs.Add(x => x.GetType().GetProperty(property.Name).GetValue(x, null) == property.GetValue(criteria, null));
}

但是，你确定需要这样做吗？可能有更好的方法来重构代码，这样就不需要使用反射来比较在两个不相关的对象上碰巧具有相同名称的属性。

从Object </t，>创建Dynamic Func <t，tresult =“”>

2 个答案: