Question

void searchForPopulationChange()
  {
     String goAgain;
     String response;
     int input;
     int searchCount = 0;
     boolean found = false;
     boolean search = false; 


     while(search == false)
     {

        System.out.println ("Enter the Number for Population Change to be found: ");
        input = scan.nextInt();


        for (searchCount = 0; searchCount < populationChange.length; searchCount++)
        {
           if (populationChange[searchCount] == input)
           {
              System.out.print(""+countyNames[searchCount]+" County / City with a population of "+populationChange[searchCount]+" individuals\n");
              found = true;
           } 

        }

        if (found == false) {
           System.out.println("No records found!");
        }


        System.out.println("\n\n-------------------------------------------------------------------------");
        System.out.println("\n\tDo you want to enter data for another Course? Type Yes or No: "); 
        response = scan.nextLine(); //the response is already recognized - thus ends or restarts the program      

        if (response.equalsIgnoreCase("yes"));
        {
           search = false;
        }

        if (response.equalsIgnoreCase("no"));
        {
           search = true;
        }      



     }


  }

} 你好！到目前为止这是我的程序，基本上，当while循环结束时，如果他希望再次执行程序，我需要它来提示用户。是还是不是？我得到提示打印但是，扫描功能不起作用。有什么建议吗？

Answer 1

从

中删除分号

if (response.equalsIgnoreCase("yes"));

和

if (response.equalsIgnoreCase("no"));

Answer 2

你的另一个问题（在if之后的分号旁边）将是nextLine在nextInt之后使用不会消耗新线标的事实，所以首先{{1}将返回空字符串。要摆脱它，试试

nextLine

或

input = scan.nextInt();
scan.nextLine();//to consume new line mark

试图得到是//没有提示工作。不会接受回复

2 个答案: