我有这个文件类型过滤器:
public const string Png = "PNG Portable Network Graphics (*.png)|" + "*.png";
public const string Jpg = "JPEG File Interchange Format (*.jpg *.jpeg *jfif)|" + "*.jpg;*.jpeg;*.jfif";
public const string Bmp = "BMP Windows Bitmap (*.bmp)|" + "*.bmp";
public const string Tif = "TIF Tagged Imaged File Format (*.tif *.tiff)|" + "*.tif;*.tiff";
public const string Gif = "GIF Graphics Interchange Format (*.gif)|" + "*.gif";
public const string AllImages = "Image file|" + "*.png; *.jpg; *.jpeg; *.jfif; *.bmp;*.tif; *.tiff; *.gif";
public const string AllFiles = "All files (*.*)" + "|*.*";
static FilesFilters()
{
imagesTypes = new List<string>();
imagesTypes.Add(Png);
imagesTypes.Add(Jpg);
imagesTypes.Add(Bmp);
imagesTypes.Add(Tif);
imagesTypes.Add(Gif);
}
OBS:.NET中是否有默认过滤器或免费库?
我需要一个静态方法来检查字符串是否是图像。你会如何解决这个问题?
//ext == Path.GetExtension(yourpath)
public static bool IsImageExtension(string ext)
{
return (ext == ".bmp" || .... etc etc...)
}
使用Jeroen Vannevel EndsWith的解决方案。我认为没关系。
public static bool IsImageExtension(string ext)
{
return imagesTypes.Contains(ext);
}
答案 0 :(得分:15)
您可以使用.endsWith(ext)
。这不是一个非常安全的方法:我可以将'bla.jpg'重命名为'bla.png',它仍然是一个jpg文件。
public static bool HasImageExtension(this string source){
return (source.EndsWith(".png") || source.EndsWith(".jpg"));
}
This提供了更安全的解决方案:
string InputSource = "mypic.png";
System.Drawing.Image imgInput = System.Drawing.Image.FromFile(InputSource);
Graphics gInput = Graphics.fromimage(imgInput);
Imaging.ImageFormat thisFormat = imgInput.rawformat;
答案 1 :(得分:14)
private static readonly string[] _validExtensions = {"jpg","bmp","gif","png"}; // etc
public static bool IsImageExtension(string ext)
{
return _validExtensions.Contains(ext.ToLower());
}
如果您希望能够在运行时配置列表而无需重新编译,请添加以下内容:
private static string[] _validExtensions;
private static string[] ValidExtensions()
{
if(_validExtensions==null)
{
// load from app.config, text file, DB, wherever
}
return _validExtensions
}
public static bool IsImageExtension(string ext)
{
return ValidExtensions().Contains(ext.ToLower());
}
答案 2 :(得分:5)
此方法会自动为OpenFileDialog
创建过滤器。它使用Windows支持的图像解码器的信息。它还添加了“未知”图像格式的信息(请参阅default
语句的switch
个案例。)
private static string SupportedImageDecodersFilter()
{
ImageCodecInfo[] encoders = ImageCodecInfo.GetImageEncoders();
string allExtensions = encoders
.Select(enc => enc.FilenameExtension)
.Aggregate((current, next) => current + ";" + next)
.ToLowerInvariant();
var sb = new StringBuilder(500)
.AppendFormat("Image files ({0})|{1}", allExtensions.Replace(";", ", "),
allExtensions);
foreach (ImageCodecInfo encoder in encoders) {
string ext = encoder.FilenameExtension.ToLowerInvariant();
// ext = "*.bmp;*.dib;*.rle" descr = BMP
// ext = "*.jpg;*.jpeg;*.jpe;*.jfif" descr = JPEG
// ext = "*.gif" descr = GIF
// ext = "*.tif;*.tiff" descr = TIFF
// ext = "*.png" descr = PNG
string caption;
switch (encoder.FormatDescription) {
case "BMP":
caption = "Windows Bitmap";
break;
case "JPEG":
caption = "JPEG file";
break;
case "GIF":
caption = "Graphics Interchange Format";
break;
case "TIFF":
caption = "Tagged Image File Format";
break;
case "PNG":
caption = "Portable Network Graphics";
break;
default:
caption = encoder.FormatDescription;
break;
}
sb.AppendFormat("|{0} ({1})|{2}", caption, ext.Replace(";", ", "), ext);
}
return sb.ToString();
}
像这样使用:
var dlg = new OpenFileDialog {
Filter = SupportedImageDecodersFilter(),
Multiselect = false,
Title = "Choose Image"
};
上面的代码(稍加修改)可用于查找可用的图像文件扩展名。为了测试给定的文件扩展名是否表示图像,我将有效的扩展名放在HashSet
中。 HashSets有一个
O(1)访问时间!确保选择不区分大小写的字符串比较器。由于文件扩展名不包含重音或非拉丁字母,因此可以安全地忽略文化。因此,我使用序数字符串比较。
var imageExtensions = new HashSet<string>(StringComparer.OrdinalIgnoreCase);
imageExtensions.Add(".png");
imageExtensions.Add(".bmp");
...
并测试文件名是否为图像:
string extension = Path.GetExtension(filename);
bool isImage = imageExtensions.Contains(extension);
答案 3 :(得分:4)
一个选项是拥有所有可能的有效图像扩展的列表,然后该方法只检查提供的扩展是否在该集合中:
private static readonly HashSet<string> validExtensions = new HashSet<string>()
{
"png",
"jpg",
"bmp"
// Other possible extensions
};
然后在验证中,您只需检查:
public static bool IsImageExtension(string ext)
{
return validExtensions.Contains(ext);
}
答案 4 :(得分:1)
我只需要做类似的事情。这是我的解决方案:
Error in if (k <= 0.8 && any(rr > (strwidth("W") * fsize/2))) rr <- rr/max(rr) * :
missing value where TRUE/FALSE needed