Question

我正在尝试完成上述功能，但收效甚微。我正在使用带有2列和2行的GridLayout来向用户显示类似拼图的游戏，其中有4个（200x200像素）JPanels（3个彩色，1个默认bgColor），它们填充整个contentPane。如果面板位于灰色面板旁边，则单击彩色面板将在评估中解析。如果是这样，他们应该交换。我完成了最后一步的每一步，他们交换了。这是代码：

public class MainClass extends JFrame {
//Generated
private static final long serialVersionUID = 4710628273679698058L;

private SpecialPanel redPanel;
private SpecialPanel greenPanel;
private SpecialPanel yellowPanel;
private SpecialPanel grayPanel;

public MainClass() {
    super("Puzzle");

    initPanels();

    setSize(410, 410);
    setLayout(new GridLayout(2, 2));

    this.add(redPanel);
    this.add(greenPanel);
    this.add(grayPanel);
    this.add(yellowPanel);
}
private void initPanels() {
    redPanel = new SpecialPanel();
    greenPanel = new SpecialPanel();
    yellowPanel = new SpecialPanel();
    grayPanel = new SpecialPanel();

    grayPanel.setGreyPanel(true);

    redPanel.setBackground(Color.RED);
    greenPanel.setBackground(Color.GREEN);
    yellowPanel.setBackground(Color.YELLOW);
    grayPanel.setBackground(this.getBackground());

    redPanel.setSize(200, 200);
    greenPanel.setSize(200, 200);
    yellowPanel.setSize(200, 200);
    grayPanel.setSize(200, 200);

    MouseAdapter ma = new MouseAdapter() {

        @Override
        public void mouseClicked(MouseEvent arg0) {
            super.mouseClicked(arg0);

            SpecialPanel sp = (SpecialPanel) arg0.getComponent();

            if (sp.getIsGray()) {
                //Do nothing
            } else if (checkIfNeighbourToGray(sp, grayPanel)) {
                //Swap them
                System.out.println("Swap notification");
                swap(sp, grayPanel);                
                //Update UI
            } else {
                //Again, do nothing for the clicked panel is diagonal to the gray panel
            }
        }

        private boolean checkIfNeighbourToGray(SpecialPanel sp, SpecialPanel grayPanel) {

            Point startPointSp = sp.getLocation();
            double x = startPointSp.getX();
            double y = startPointSp.getY();

            double width = sp.getWidth();
            double height = sp.getHeight();

            Point grayPoint = grayPanel.getLocation();
            double xG = grayPanel.getX();
            double yG = grayPanel.getY();

            double widthG = grayPanel.getWidth();
            double heightG = grayPanel.getHeight();

            //Gray panel is RIGHT of clicked one
            if (x + width == xG && y + height == yG + heightG) {
                return true;                    
            }
            //Gray panel is LEFT of clicked one
            else if (x - width == xG && y + height == yG + heightG) {
                return true;
            }
            //Gray panel is ABOVE of clicked one
            else if (x == xG && x + width == xG + widthG) {
                return true;
            }
            //Gray panel is UNDER of clicked one
            else if (xG == x && yG + widthG == x + width) {
                return true;
            }

            return false;
        }

        private void swap(SpecialPanel sp, SpecialPanel grayPanel) {
            //Swap logic
        }

    };
    redPanel.addMouseListener(ma);
    greenPanel.addMouseListener(ma);
    yellowPanel.addMouseListener(ma);
    grayPanel.addMouseListener(ma);

}
public static void main(String[] args) {
    MainClass mc = new MainClass();
    mc.setVisible(true);

}

}

类SpecialPanel正在扩展JPanel，只有一个新的布尔属性IsGrayPanel最初设置为false + getter和setter。注意：这是以“我有基本的Swing技能”的方式完成的，虽然我在此期间学到了更多关于java swing的知识，但我当时只是受限于基本的swing功能，所以我应该保持这种方式。因此我的问题是如何正确交换彼此相邻的两个面板，包括UI更新？

Answer 1

不需要将JPanels移动到容器中，否则你需要使用大量无用的代码从contianer中删除两个JPanels indexes然后使用swaping indexes，
（仅限约Color）仅在两个setBackground(Color.Xxx)之间交换JPanels
puzzle-like game约为Images，谜题或者是minesweaper，（不清楚......）
1. 将Images作为Icon/ImageIcons添加到JLabel而不是JPanel，将Mouse Events添加到setIcon()以Icons 1}}之间JLabels，加载Icons到本地变量
2. （最简单的方法）JToggleButton and Icon，有关于JLabel的逻辑类似物，但关于在Icon上显示setPressedIcon()

Answer 2

我不确定这是否有效。看起来太容易了。

JPanel tempPanel = sp;
sp = grayPanel;
grayPanel = tempPanel;

this.setVisible(false);
this.setVisible(true);
this.validate(); //try this first
this.repaint(); // if it doesnt work, add this function.

以编程方式在JFrame中交换两个JPanel

2 个答案: