Question

我想创建一个Chrome扩展程序，点击它后，获取当前标签的URL并将其传递给我的MySQL表格。这是我到目前为止所处的位置：

Manifest.json

{

  "name": "Markr",
  "version": "1.0.10",
  "manifest_version": 2,
  "description": "The ultimate bookmarking tool",
  "icons": { "32": "icon.png" },
  "default_icon": "icon.png",
  "default_popup": "bookmark.html"
   },
   "permissions": [
      "tabs",
      "http://*/*"],
  "offline_enabled": false
}

bookmark.html

<!DOCTYPE html>
<html>
<head>
        <link rel="stylesheet" type="text/css" href="style.css">
        <script src="script_v3.js"></script>
        <script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js" ></script>
</head>

<body>
    <h1>This site has been bookmarked.</h1>
</body>
</html>

script_v3.js

$(document).ready(function(){
        var taburl;
    chrome.tabs.query({
        active: true,
        lastFocusedWindow: true
    }, function(array_of_Tabs){
        var tab = array_of_Tabs[0];
        taburl = tab.url;
    });

        $.ajax({
        url: "http://localhost/markit/site/base.php", 
        type: "POST", //default is GET
        data: {
           var taburl: url;
    }
        crossDomain:true,
        cache:false,
        async:false,
    });
});

base.php

<?php
$url = $_REQUEST["url"];

mysql_connect("localhost", "root", "") or die(mysql_error());
echo "Connected to MySQL<br />";
mysql_select_db("bookmarks") or die(mysql_error());
echo "Connected to Database";
mysql_query($write = "INSERT INTO links (url) VALUES ($url)");

?>

为什么不起作用？

Chrome的书签扩展程序无法正常工作

0 个答案: