Question

data1=[{'aa': None, 'bb': 'dffg', 'cc': '0', 'dd': '1234', 'ee': None}, 
{'aa': 'cdfg', 'bb': None, 'cc': '0', 'dd': 'sc12', 'ee': 'edft'},
{'aa': 'bvkjdi', 'bb': 'hdjd', 'cc': '0', 'dd': None, 'ee': None},
{'aa': None, 'bb': None, 'cc': '0', 'dd': '123dg', 'ee': 'hddk'}]


data2={'aa': ('','cdfg', 'bvkjdi', ''), 'bb': ('dffg','', 'hdjd', ''),
'cc': ('0', '0', '0','0'), 'dd': ('1234', 'sc12', '','123dg'),
'ee': ('', 'edft', '','hddk') }

data1是列表，其中许多字典及其键值和data2是带有键值的字典。需要比较这两个但格式不同。需要弄清楚比较'aa'的data1到'的简单方法aa'从data2，'bb'值data2到'bb'值的data2类似于剩下的东西。请帮我比较一下。

Answer 1

您可以执行以下操作：

>>> data1_like_data2 = {}
>>> for item in data1:
...     for key in item:
...         try:
...             data1_like_data2[key] += (item[key],)
...         except:
...             data1_like_data2.update({key:(item[key],)})
>>> data1_like_data2
{'aa': (None, 'cdfg', 'bvkjdi', None), 'cc': ('0', '0', '0', '0'), 'dd': ('1234', 'sc12', None, '123dg'), 'ee': (None, 'edft', None, 'hddk'), 'bb': ('dffg', None, 'hdjd', None)}

然后直接比较它们，

>>> data1_like_data2 == data2:
>>> False

由于无和'0'问题，它给出了假。根据您的要求对其进行排序，然后就可以了。

Answer 2

假设None =＆＃39;＆＃39;并且0 =＆＃39; 0＆＃39; 我想这就是你想要的：

data1=[{'aa': None, 'bb': 'dffg', 'cc': 0, 'dd': '1234', 'ee': None}, 
{'aa': 'cdfg', 'bb': None, 'cc': 0, 'dd': 'sc12', 'ee': 'edft'},
{'aa': 'bvkjdi', 'bb': 'hdjd', 'cc': 0, 'dd': None, 'ee': None},
{'aa': None, 'bb': None, 'cc': 0, 'dd': '123dg', 'ee': 'hddk'}]


data2={'aa': ('','cdfg', 'bvkjdi', ''), 'bb': ('dffg','', 'hdjd', ''),
'cc': ('0', '0', '0','0'), 'dd': ('1234', 'sc12', '','123dg'),
'ee': ('', 'edft', '','hddk') }

results = {}
for key in data2:
    set1 = [x[key] for x in data1]
    set1 = [str(x) if x is not None else '' for x in set1]
    set2 = list(data2[key])

    results[key] = set1 == set2        
# results = {'aa': True, 'cc': True, 'dd': True, 'ee': True, 'bb': True}

Answer 3

您可以使用词典理解将data1重组为data2：

>>> n = {k: tuple(d[k] for d in data1) for k in data2}
>>> n
{'aa': (None, 'cdfg', 'bvkjdi', None), 'cc': ('0', '0', '0', '0'), 
'dd': ('1234', 'sc12', None, '123dg'), 'ee': (None, 'edft', None, 'hddk'), 
'bb': ('dffg', None, 'hdjd', None)}

由于您希望None与''匹配，我们也可以转换它们：

>>> n = {k: tuple(d[k] if d[k] is not None else '' for d in data1) for k in data2}
>>> n
{'aa': ('', 'cdfg', 'bvkjdi', ''), 'cc': ('0', '0', '0', '0'), 
'dd': ('1234', 'sc12', '', '123dg'), 'ee': ('', 'edft', '', 'hddk'), 
'bb': ('dffg', '', 'hdjd', '')}

之后：

>>> n == data2
True

如果您只想比较aa和bb键/值对，可以将它们拉出来：

>>> keys_to_compare = {'aa', 'bb'}
>>> d1 = {k: tuple(d[k] if d[k] is not None else '' for d in data1) for k in keys_to_compare}
>>> d2 = {k: v for k,v in data2.iteritems() if k in keys_to_compare}
>>> d1 == d2
True

或者就地比较它们：

>>> all(tuple(d[k] if d[k] is not None else '' for d in data1) == data2[k] for k in keys_to_compare)
True

将列表与字典进行比较？

3 个答案: