Question

我的表单类型有一个集合字段：

$builder->add('affiliates', 'collection', array(
    'type' => new AffiliateFormType(),
    'allow_add' => true, 
    'allow_delete' => true, 
    'by_reference' => false,
));

在模板中我有：

<table id="affiliates" >
    <tr>
        <th class="t1c0"></th>
        <th class="t1c1" data-prototype="{{ form_widget(form.affiliates.vars.prototype.affiliate_name)|e }}">Name</th>
        <th class="t1c2" data-prototype="{{ form_widget(form.affiliates.vars.prototype.affiliate_type_code)|e }}">Type</th>
        <th class="t1c3" data-prototype="{{ form_widget(form.affiliates.vars.prototype.address)|e }}">Address</th>
    </tr>
    {% for affiliate in form.affiliates %}
    <tr>
        <td class="t1c0"><input type="button" class="delete_button" value="Delete"/></td>
        <td class="t1c1">{{ form_widget(affiliate.affiliate_name) }}{{ form_errors(affiliate.affiliate_name) }}</td>
        <td class="t1c2">{{ form_widget(affiliate.affiliate_type_code) }}{{ form_errors(affiliate.affiliate_type_code) }}</td>
        <td class="t1c3">{{ form_widget(affiliate.address) }}{{ form_errors(affiliate.address) }}</td>
    </tr>
    {% endfor %}
</table>
<input type="button" class="add_button" value="Add line" onclick="addAffiliate();"/>

现在用于添加/删除行的javasript代码（带有jquery）是：

<script language="javascript">

    var affiliatesCollection = $('table#affiliates');

    $(document).ready(function(){
        var rowCount = $('table#affiliates tr').length;
        affiliatesCollection.data('index', rowCount - 1);

        $('.delete_button').click(function(e) {
            $(this).closest("tr").remove();
        });
    });

    function addAffiliate() {
        //get index
        var index = affiliatesCollection.data('index');
        affiliatesCollection.data('index', index + 1);

        //add row
        var cells = new Array();
        var cell = $('<input type="button" class="delete_button" value="Delete"/>').click(function (){
            $(this).closest("tr").remove();
        });
        var $cell = $('<td></td>').append(cell);
        cells[0] = $cell;

        for (var i = 1; i < 4; i++)
        { 
            var prototype = $('th.t1c'.concat(i)).data('prototype');
            var cell = prototype.replace(/__name__/g, index);
            var $cell = $('<td></td>').append(cell);
            cells[i] = $cell;
        }
        var $newRow = $('<tr></tr>').append(cells);
        affiliatesCollection.append($newRow);
    }

</script>

假设名称是必填字段。除了一种情况之外，上面的代码工作正常：当添加并删除并再次添加行时，删除的索引不再可用，例如第一行的索引= 1，第二行的索引= 3;当提交无效表单时（例如，name字段为空），form.isValid（）正确返回false，但验证错误未显示在各自元素下方。有人可以帮我纠正这个问题吗？谢谢。

Answer 1

看看Bernhard Schussek对此的评论：

How can I add a violation to a collection?

您必须为集合明确设置error_bubbling到false（默认为true），以防止错误将树冒泡到您的主窗体并在那里显示为全局错误

正如您（在我的问题中可以看到的）在模板中没有{% form_errors(form) %}这些全局表单错误未显示但是您的集合错误现在应该在表单中显示为全局错误。

symfony 2，表单集合，验证错误

1 个答案: