我在Qt上为客户端编写了一个程序,用于从服务器接收数据,但它没有接收数据并将接收的字节显示为零,以下是我的程序:
// client.h
#ifndef CLIENT_H
#define CLIENT_H
#include <QObject>
#include <QString>
#include <QtNetwork/QTcpSocket>
class Client: public QObject
{
Q_OBJECT
public:
Client(QObject* parent = 0);
~Client();
void start(QString address, quint16 port);
void send(const char*);
void receive();
public slots:
void startTransfer();
private:
QTcpSocket client;
};
#endif // CLIENT_H
// client.cpp
#include "client.h"
#include <QtNetwork/QHostAddress>
#include<QIODevice>
Client::Client(QObject* parent): QObject(parent)
{
connect(&client, SIGNAL(connected()),
this, SLOT(startTransfer()));
//connect(&client, SIGNAL(waitForBytesWritten()),
// this, SLOT(receive()));
}
Client::~Client()
{
client.close();
}
void Client::start(QString address, quint16 port)
{
QHostAddress addr(address);
client.connectToHost(addr, port);
}
void Client::startTransfer()
{
client.write("Connection Established", 22);
}
void Client::send(const char *buffer)
{
client.write(buffer,sizeof(buffer));
}
void Client::receive()
{
char temp[1024] = {0};
int len = client.read(temp,client.bytesAvailable());
printf("\tData recieved from server :: %s\n",temp);
printf("\tSize of data received is :: %d\n",client.bytesAvailable());
printf("\tBytes read is :: %d\n",len);
}
// main.cpp中
#include <QCoreApplication>
#include "client.h"
//#include <QApplication>
int main(int argc, char *argv[])
{
QCoreApplication a(argc, argv);
Client client;
client.start("192.168.1.2", 9602);
char buff[] = "Send operation performed from main";
client.send(buff);
// while(1)
client.receive();
return a.exec();
}
这里我的程序功能执行然后停止接收(可能是),当我从服务器发送任何东西时它不需要任何东西。任何建议? 如果我做了任何愚蠢的编程错误,我不是粗鲁的,因为我是新手。
答案 0 :(得分:0)
您可以尝试使用while(1)并在其中编写接收函数
答案 1 :(得分:0)
你没有得到@Merlin069的回答....你应该在信号的位置使用readyRead,你的接收函数作为插槽......它会起作用。我希望你能理解这么简单的语言。