jQuery选择带有下一个prev按钮的ul li项目

时间:2013-07-17 18:04:06

标签: jquery

我尝试使用prev下一个按钮选择li元素,目前正在使用此代码:http://jsfiddle.net/KzyAY/41/但是如果你继续点击next / prev它会继续使用ul元素。任何想法我如何选择内部ul?谢谢!

这里小提琴:http://jsfiddle.net/KzyAY/41/

<ul class='selected' id="">
<li id="">1</li>
<li id="">2</li>
<li id="">3</li>
</ul>
<div>Current tag:<span id="current-tag"></span></div>
<button id="prev">Previous</button>
<button id="next">Next</button>

JS:

(function($) {
    $.fn.domNext = function() {
        return this
            .children(":eq(0)")
            .add(this.next())
            .add(this.parents().filter(function() {
                return $(this).next().length > 0;
            }).next()).first();        
    };

    $.fn.domPrevious = function() {
        return this
            .prev().find("*:last")   
            .add(this.parent())     
            .add(this.prev())
            .last();         
    };
})(jQuery);

$("#next").click(function() {
    var $next, $selected = $(".selected");

    $selected.removeClass("selected");
    $next = $selected.domNext().addClass("selected");
    if ($next.length) {
        $("#current-tag").text($next.attr('class'));
    }
});

$("#prev").click(function() {
    var $prev, $selected = $(".selected");
    $selected.removeClass("selected");
    $prev = $selected.domPrevious().addClass("selected");
    if ($prev.length) {
        $("#current-tag").text($prev.get(0).tagName);
    }

});

4 个答案:

答案 0 :(得分:9)

对插件不确定。因为对于简单的事情来说肯定是一种矫枉过正。

但我会写下来

var $first = $('li:first', 'ul');
var $last = $('li:last', 'ul');

// Have the first and last li's set to a variable
$("#next").click(function () {

    var $next;
    var $selected = $(".selected");
    // get the selected item
    // If next li is empty , get the first
    $next = $selected.next('li').length ? $selected.next('li') : $first;
    $selected.removeClass("selected");
    $next.addClass('selected');
});

$("#prev").click(function () {
    var $prev,
        $selected = $(".selected");
    // get the selected item
    // If prev li is empty , get the last
    $prev = $selected.prev('li').length ? $selected.prev('li') : $last;
    $selected.removeClass("selected");
    $prev.addClass('selected');
});

<强> Check Fiddle

答案 1 :(得分:1)

我认为你只需要这个代码,Jquery中已有prev和next函数:

$("#next").click(function() {
    var currentSelect = $('ul > .selected');
     if (currentSelect.next().length == 0)
   {
         $('ul > li:first').addClass('selected');
    }
    else
     { 
         currentSelect.next().addClass('selected');
      }
          currentSelect.removeClass('selected');
});

$("#prev").click(function() {
    var currentSelect = $('ul > .selected');
     if (currentSelect.prev().length == 0)
   {
         $('ul > li:last').addClass('selected');
    }
    else
     { 
         currentSelect.prev().addClass('selected');
      }
          currentSelect.removeClass('selected');
});

答案 2 :(得分:1)

使用此标记:

<ul class='list' id="list">
    <li id="" class="selected">1</li>
    <li id="">2</li>
    <li id="">3</li>
</ul>
<div>Current tag:<span id="current-tag"></span>

</div>
<button id="prev">Previous</button>
<button id="next">Next</button>
你可以这样做:

var list = $('#list').find('>li');
$("#prev,#next").click(function (event) {
    var $new, $selected = $(".selected");
    $new = (event.target.id == "prev") ? ($selected.index() == 0 ? list.last() : $selected.prev()) : ($selected.index() == list.last().index() ? list.first() : $selected.next());
    $selected.removeClass("selected");
    $new.addClass("selected");
    $("#current-tag").text($new.attr('class') + $new.index());
});

查看实际操作:http://jsfiddle.net/5CJzE/

答案 3 :(得分:0)

假设“已选择”的LI将具有“活动”类。

<ul class='selected'>
<li>1</li>
<li>2</li>
<li>3</li>
</ul>

JS:

$("#next").click(function() {
    move(1);
})

$("#prev").click(function() {
   move(-1)
})

function move(dir) {
     var active = 0;
     var ind = $(target).find('li.active').index('.selected')
     if(ind==-1) {
        active = 0;
     }
     active = active+dir;
     $('.selected li.active').removeClass('active');
     if(active<0) {
         active=0;
     }
     if(active>$('.selected li').length()) {
         active=$('.selected li').length();
     }
     $('.selected li').eq(active-1).addClass('active');
}