Question

如果我想编写一个使用参数启动Firefox的应用程序？

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Diagnostics;

namespace Launcher
{
  public static class Program
  {
    public static void Main(string[] args)
    {
      Process.Start("C:/Program Files/Mozilla Firefox/firefox.exe");//this is ok
      Process.Start("C:/Program Files/Mozilla Firefox/firefox.exe -P MyProfile -no-remote");// this doesn't work
    }
  }
}

Answer 1

您需要指定process.StartInfo.Arguments

请参阅此问题：Calling an application from ASP.NET MVC

Answer 2

您需要使用process.StartInfo.Arguments，如下所示：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Diagnostics;

namespace Launcher
{
  public static class Program
  {
    public static void Main(string[] args)
    {

        Process firefox = new Process();

        firefox.StartInfo.FileName = @"C:\Program Files\Mozilla Firefox\firefox.exe";
        firefox.StartInfo.Arguments = "-P MyProfile -no-remote";

        firefox.Start();

    }
  }
}

如何使用C＃中的参数编写启动应用程序的应用程序？

2 个答案: