Question

我有一个SQL查询，根据雇用日期（周年纪念日）计算员工工作的天数。但是，这些天包括周末，所以我需要排除星期六和星期日。我尝试使用DATEADD(dw, ...)，但它没有用。

SELECT PRCo, Employee,LastName, FirstName, MidName,SSN,HireDate,
(case when 
      DATEADD(year, datediff(year, HireDate, getdate()), HireDate) < GETDATE()
 then DATEDIFF(dd, DATEADD(year, datediff(year, HireDate, getdate()), HireDate), getdate())
 else DATEDIFF(dd, DATEADD(year, datediff(year, HireDate, getdate()) - 1, HireDate),
               getdate()) end) as HRSDATE
FROM dbo.PREH

Answer 1

实现此目的的一种简单方法是创建一个日历表，其中日期，星期几和日期都加载到表中。然后，您只需选择员工开始日期的日期，即星期几！=星期六或星期日。

Answer 2

只是从结果中减去2 * number of weeks？

Answer 3

使用合适的日历表，你可能会写这样的东西。（假设雇用日期是2011-01-15。）日历表的一大优势是可以看到代码显然正确。

select count(*) as num_weekdays
from calendar
where cal_date between '2011-01-15' and current_date
  and day_of_week not in ('Sat', 'Sun');

更简单，如果您创建一个名为“工作日”但仅包含工作日的视图。。

select count(*) as num_weekdays
from weekdays
where cal_date between '2011-01-15' and current_date;

This SO answer具有日历表的PostgreSQL代码。您可以非常轻松地为SQL Server调整它。

Answer 4

如果它需要准确，
STEP01减去2倍数整数（DATEDIFF RESULT）除以7
步骤02然后取7减去工作日（开始日期）编号（使用DATEPART）
STEP03如果它大于数字（DATEDIFF RESULT），则减去2.

DECLARE @start AS datetime = '10/24/2014'

DECLARE @end AS datetime = '10/31/2014'
SELECT CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS int)AS STEP_ONE_OrigDays
--,CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money)*(1.000*(5.000/7.000)) AS EstDays
,(2.000*(CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money)/7)) AS STEP_TWO--SUBTRACT 2 times the number integer divided by 7
,DATEPART(dw, @start) AS STEP_THREE_WEEK_DAY_NUMBER --WEEK DAY #
,7 - DATEPART(dw, @start) AS STEP_FOUR_SEVENminus_WEEK_DAY_NUMBER --7 minus WEEK DAY #
,CAST(CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money)
-(2.000*(CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money)/7))
+CASE 
WHEN (7.000-DATEPART(dw, @start)) > CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money) 
THEN -2.000
ELSE 0.000 
END AS int) AS ExactDays_NOT_IncludingDayOf --JAH EXCLUDE WEEKEND Fx NOT Including the Day of
,CAST(CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money)-(2.000*(CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money)/7))
+CASE 
WHEN (7.000-DATEPART(dw, @start)) > CAST(DATEDIFF("d",CAST(@start AS datetime),CAST(@end AS datetime)) AS money) 
THEN -2.000
ELSE 0.000 
END AS int)+1 AS ExactDays_IncludingDayOf --JAH EXCLUDE WEEKEND Fx INCLUDING the Day of

如何计算不包括周末的总天数？

4 个答案: