Question

我试图使用SQL从当前行中减去前一行的值。

SELECT 
    rd.PONum, 
    od.OrderLine, 
    rd.PartNum, 
    p.PartDescription, 
    od.OrderNum, 
    rd.OurQty, 
    od.Number01 AS Reserved, 
    CASE WHEN rd.OurQty - od.Number01 > 0 
         THEN od.Number01 
         ELSE rd.OurQty END AS Allocated, 
    rd.OurQty - od.Number01 AS NewOurQty, 
    c.CustNum, 
    c.Name
FROM dbo.RcvDtl AS rd INNER JOIN
     dbo.Part AS p ON rd.PartNum = p.PartNum INNER JOIN
     dbo.OrderDtl AS od ON rd.PartNum = od.PartNum INNER JOIN
     dbo.OrderHed AS oh ON od.OrderNum = oh.OrderNum INNER JOIN
     dbo.Customer AS c ON od.CustNum = c.CustNum
WHERE (rd.PONum = 73) 
      AND (od.Number01 > 0) 
      AND (od.OpenLine = 1)

返回值：

PONum | OrderLine | PartNum | PartDescription | OrderNum | OurQty | Reserved | Allocated | NewOurQty | CustNum | Name
73         1       10050926 Example Description    62       55         35         35          20         1032     Sam Test
73         1       10050926 Example Description    63       55         6          6           49         496     Steve Test

但我希望它能够回归：

PONum | OrderLine | PartNum | PartDescription | OrderNum | OurQty | Reserved | Allocated | NewOurQty | CustNum | Name
73         1       10050926 Example Description    62       55         35         35          20         1032     Sam Test
73         1       10050926 Example Description    63       55         6          6           14         496     Steve Test

在第1行中，NewOurQty = 20（55-35）。第2行现在需要通过计算NewOurQty（来自行n-1） - 保留（来自行n）来计算当前行的NewOurQty。

如何使用SQL检索上一行的值？

修改

我正在使用Microsoft SQL

Answer 1

您可以引入行号

SELECT @ROW := @ROW + 1 AS row, first_name
FROM users, (SELECT @ROW := 0) r;

并在子查询中添加列。然后添加join ON firstAlias.row=secondAlias.row+1

Answer 2

也许这种技术很有用（这里用ROW N-1的值加上ROW N的值）：

CREATE TABLE TEST(
    source INT
)

INSERT INTO TEST VALUES(1)
INSERT INTO TEST VALUES(10)
INSERT INTO TEST VALUES(20)
INSERT INTO TEST VALUES(30)
INSERT INTO TEST VALUES(40)
INSERT INTO TEST VALUES(50)


/*HERE THE QUERY*/
WITH temp AS (
      SELECT t.*,ROW_NUMBER() over (order by t.source) as row_num
      FROM TEST t
    )
    SELECT 
    x.source,
    x.source + ISNULL((SELECT y.source FROM temp y WHERE y.row_num = x.row_num - 1),0)  AS SUM_ACUMULATE    
FROM temp x

您可以尝试 here 。

SQL查询使用上一行的值

2 个答案: