好的,这就是我需要的......
示例输入:
$str = "Well, I guess I know what this # is : it is a & ball";
示例输出:
firstWords($str,5)
应该返回Array("Well","I","guess","I","know")
lastWords($str,5)
应该返回Array("is","it","is","a","ball")
我已尝试使用自定义正则表达式和str_word_count
,但我仍然觉得我错过了某些东西。
有什么想法吗?
答案 0 :(得分:6)
你需要的只是
$str = "Well, I guess I know what this # is : it is a & ball";
$words = str_word_count($str, 1);
$firstWords = array_slice($words, 0,5);
$lastWords = array_slice($words, -5,5);
print_r($firstWords);
print_r($lastWords);
输出
Array
(
[0] => Well
[1] => I
[2] => guess
[3] => I
[4] => know
)
Array
(
[0] => is
[1] => it
[2] => is
[3] => a
[4] => ball
)
答案 1 :(得分:0)
function cleanString($sentence){
$sentence = preg_replace("/[^a-zA-Z0-9 ]/","",$sentence);
while(substr_count($sentence, " ")){
str_replace(" "," ",$sentence);
}
return $sentence;
}
function firstWord($x, $sentence){
$sentence = cleanString($sentence);
return implode(' ', array_slice(explode(' ', $sentence), 0, $x));
}
function lastWord($x, $sentence){
$sentence = cleanString($sentence);
return implode(' ', array_slice(explode(' ', $sentence), -1*$x));
}
答案 2 :(得分:0)
这是firstWord:
function firstWords($word, $amount)
{
$words = explode(" ", $word);
$returnWords = array();
for($i = 0; $i < count($words); $i++)
{
$returnWords[] = preg_replace("/(?![.=$'€%-])\p{P}/u", "", $words[$i]);
}
return $returnWords;
}
for lastWords reverse for loop。