选择具有列的多个值的行

时间:2013-07-17 10:38:16

标签: mysql sql rows

在MySQL上,给出下表(image_tags):

image_id | tag_id
-----------------
1        | 100
1        | 20
2        | 100
3        | 20

我想选择tag_id = 100 AND tag_id = 20的行,在这种情况下我想要的结果是:

image_id
--------
1        

我试过,但我找不到在纯SQL中执行此操作的正确方法。谢谢!

7 个答案:

答案 0 :(得分:3)

假设(image_idtag_id)对是唯一的:

SELECT image_id
FROM image_tags
WHERE tag_id IN ('20', '100')
GROUP BY image_id
HAVING count(*) = 2

答案 1 :(得分:1)

试试这个:

SELECT image_id FROM MyTable
WHERE tag_id IN (100,20)
GROUP BY image_id
HAVING COUNT(*) = 2

如果您想选择每一行,请尝试以下一行:

SELECT * FROM MyTable
WHERE image_id IN
(
    SELECT image_id FROM MyTable
    WHERE tag_id IN (100,20)
    GROUP BY image_id
    HAVING COUNT(*) = 2
)

请参阅this SQLFiddle

答案 2 :(得分:1)

简单的JOIN查询

SELECT a.image
FROM image_tags a
INNER JOIN image_tags b ON a.image_id = b.image_id AND b.tag_id = 20
WHERE a.tag_id = 100

或使用计数,但如果图像有重复标签,则应对

SELECT DISTINCT image_id
FROM image_tags
WHERE tag_id in ('20', '100')
GROUP BY image_id
HAVING count(DISTINCT tag_id) = 2

答案 3 :(得分:0)

你所做的是对的,你也可以尝试这个

  

从image_tags中选择*其中tag_id in('100','20',....)

答案 4 :(得分:0)

SELECT Image_ID FROM 
(SELECT Image_ID FROM tab
WHERE Tag_ID = 100) tag100
JOIN
(SELECT Image_Id FROM tab
WHERE TagID = 20) tag20

我认为这就是你在寻找的东西 - 你想要那些TagID等于20且TagID等于100的记录,对吗?

答案 5 :(得分:0)

select image_id 
from image_tags 
where image_id IN (
            select image_id 
            from image_tags 
            where tag_id = 100) 
AND tag_id = 20

答案 6 :(得分:0)

您可以使用

select image_id from test
where image_id IN (select image_id from test
where tag_id = '100') AND tag_id = '20'

检查Demo