我有一个如下所示的数组：
Array
(
[owner] => user_id
[add_owner] => imagetype
[cache] => cc118e60798c3369f4cc0a544f671e9c
[link] => Array
(
[0] => http://cibooo
[1] => http://teamimage
)
[imagetype] => Array
(
[0] => 8
[1] => 9
)
[email] => Array
(
[0] => cibooo@mai.com
)
)
如您所见，某些键有多个值。 我想要做的是当数组包含内部具有更多值的键时，将生成以下数组。
Array
(
[images] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://cibooo
[imagetype] => 8
[email] => cibooo@mai.com
)
[images] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://teamimage
[imagetype] => 9
[email] => cibooo@mai.com
)
)
现在我做的是以下内容：
foreach ($updates as $update) {
if (isset($data[$update['start_param']]) || $update['start_param'] == 'any') {
/*
* We check if the update input value is empty, if so
* we replace it with an alternative value.
* This alternative value can be the value of the input data
* in the case that it's available, if not it is replaced
* with the value of the input data that corresponds to the
* start_param of each update input.
* If the start_param is 'any' it gets ignored.
*/
$update_value_alternative = isset($data[$update['name']]) ? $data[$update['name']] : isset($data[$update['start_param']]) ? $data[$update['start_param']] : NULL;
$update_value = !$this->check->isEmpty($update['value']) ? $update['value'] : $update_value_alternative;
/*
* owner and add_owner must be the same for the update inputs
* of the same table, so we do not mind if the $vals['owner']
* and $vals['add_owner'] is replaced on each loop for the update inputs
* of the same table.
*/
$vals['owner'] = $update['owner'];
$vals['add_owner'] = $update['add_owner'];
/*
* We add the cache on each loop, will be deleted for
* those tables that do not contain a cache column.
*/
$vals['cache'] = $this->generate('generate->hash');
/*
* The names of all the update inputs and their relative
* values.
* The values are passed through the generate() method
* in order to generate a unique ID or a specific value
* based on what has been inserted in each specific update
* input value. Example: generate->hash
*/
$vals[$update['name']][] = $this->generate($update_value, $update['owner'], $request, $data);
$tables[$update['table']] = $vals;
}
}
在脚本的最底部，您可以看到我是如何生成数组的。
问题是最终数组如下，而不是在为$updates数组上的每个键找到更多值时创建不同的数组。
当$tables[$update['table']]包含每个键的更多值时，我需要了解如何创建不同的数组$vals[$update['name']][]。我怎样才能做到这一点？
这是我用我的代码得到的数组。
Array
(
[images] => Array
(
[owner] => user_id
[add_owner] => imagetype
[cache] => 8669e31741b5d7c0f471167dca38cd4e
[link] => Array
(
[0] => http://cibooo
[1] => http://teamimage
)
[imagetype] => Array
(
[0] => 8
[1] => 9
)
[email] => Array
(
[0] => cibooo@mai.com
)
)
)
答案 0 :(得分：0)
这非常棘手，因为如果你有3个链接2个图像类型，一个电子邮件会发生什么？我建议你使用排列代替生成不同的可能性而不是填充元素。
我是什么意思？
$data = array(
'owner' => 'user_id',
'add_owner' => 'imagetype',
'cache' => 'cc118e60798c3369f4cc0a544f671e9c',
'link' => array( // 2 elements
'http://cibooo',
'http://teamimage'
),
'imagetype' => array( // 3 elements
8,
9,
10
),
'email' => array(
'cibooo@mai.com' // 1 element
)
);
如何组合上述数组？
使用上面的格式会导致不一致的可能性，我认为应该这样做：
unset($data['cache']);
$values = array_filter($data, "is_array");
$keys = array_keys($values);
$new = array();
foreach(permutations($values) as $v) {
$new[] = array_merge($data, array_combine($keys, $v));
}
print_r($new);
输出
Array
(
[0] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://cibooo
[imagetype] => 8
[email] => cibooo@mai.com
)
[1] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://teamimage
[imagetype] => 8
[email] => cibooo@mai.com
)
[2] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://cibooo
[imagetype] => 9
[email] => cibooo@mai.com
)
[3] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://teamimage
[imagetype] => 9
[email] => cibooo@mai.com
)
[4] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://cibooo
[imagetype] => 10
[email] => cibooo@mai.com
)
[5] => Array
(
[owner] => user_id
[add_owner] => imagetype
[link] => http://teamimage
[imagetype] => 10
[email] => cibooo@mai.com
)
)
使用的功能
function permutations($lists) {
$permutations = array();
$iter = 0;
while(true) {
$num = $iter ++;
$pick = array();
foreach($lists as $l) {
$r = $num % count($l);
$num = ($num - $r) / count($l);
$pick[] = $l[$r];
}
if ($num > 0)
break;
$permutations[] = $pick;
}
return $permutations;
}
答案 1 :(得分：0)
许多假设：
假设总是有相同数量的图像类型，并且链接具有相同的索引，
假设总会有一封电子邮件，以及其他所有属性，
你可以遍历图像类型（这基本上就是你要分割的东西）。
例如：
//using your original array as $input:
$result = array();
$result["images"] = array();
$count = 0;
foreach($input["imagetype"] as $image_type) {
$result["images"][] = array(
"owner" => $input['owner'],
"add_owner" => $input['add_owner'],
"link" => $input['link'][$count],
"imagetype" => $image_type,
"email" => $input['email']
);
++$count;
}
print_r($result);