Question

我解析错误的地方哎呀。我在第一次询问中得到了分号。

基本上我试图在同一个PHP脚本中使用三个不同的select语句进行查询。这可能吗？（最后一个问题我保证，在此之后我认为基础知识应该让我几周而不必再问更多）

<?php
include("server_connect.php");

mysql_select_db("rnissen");

$query = "SELECT column_one, column_two, column_four FROM tbltable;"

$results = mysql_query($query) or die(mysql_error());

$querytwo = "SELECT column_one, column_two, column_five FROM tbltable WHERE column_five = 1989";

$results = mysql_query($querytwo) or die(mysql_error());

$querythree = "SELECT COUNT(column_five) FROM tbltable WHERE column_five = 1989";

$results = mysql_query($querythree) or die(mysql_error());

?>

第二部分好的，我按照建议更改了代码，并尝试将其添加到表中。我还在解析错误：语法错误，第7行的C：\ xampp \ htdocs \ 3718 \ assign5SELECT.php中的意外'$ results1'（T_VARIABLE）

我在没有桌子的情况下尝试了它，但仍然是同样的错误。有什么我想念的吗？这是带有新变量的更新代码

mysql_select_db("rnissen");

$query = "SELECT column_one, column_two, column_four FROM tbltable;"
$results1 = mysql_query($query) or die(mysql_error());
echo "Column One, Column Two, Column Four : </br>";
echo "<table border=\"1\">\n";
while ($row1 = mysql_fetch_assoc($results1)) {
echo "<tr>\n";
foreach($row1 as $value1) {
echo "<td>\n";
echo $value1;
echo "</td>\n";
}
echo "</tr>\n";
}
echo "</table>\n";

$querytwo = "SELECT column_one, column_two, column_five FROM tbltable WHERE column_five = 1989";
$results2 = mysql_query($querytwo) or die(mysql_error());
echo "Column One, Column Two, Column Five : </br>";
echo "<table border=\"1\">\n";
while ($row2 = mysql_fetch_assoc($results2)) {
echo "<tr>\n";
foreach($row2 as $value2) {
echo "<td>\n";
echo $value2;
echo "</td>\n";
}
echo "</tr>\n";
}
echo "</table>\n";

$querythree = "SELECT COUNT(column_five) FROM tbltable WHERE column_five = 1989";
$results3 = mysql_query($querythree) or die(mysql_error());
echo "Column 4 has this many 1989s : </br>";
echo "<table border=\"1\">\n";
while ($row3 = mysql_fetch_assoc($results3)) {
echo "<tr>\n";
foreach($row3 as $value3) {
echo "<td>\n";
echo $value3;
echo "</td>\n";
}
echo "</tr>\n";
}
echo "</table>\n";
?>

Answer 1

$query = "SELECT column_one, column_two, column_four FROM tbltable;"

$results = mysql_query($query) or die(mysql_error());

$querytwo = "SELECT column_one, column_two, column_five FROM tbltable WHERE column_five = 1989";

$results = mysql_query($querytwo) or die(mysql_error());

$querythree = "SELECT COUNT(column_five) FROM tbltable WHERE column_five = 1989";

$results = mysql_query($querythree) or die(mysql_error());

您遇到的问题是您使用相同的变量名称覆盖结果。

示例：

$Var = "test";
 echo $Var; // Will output "test"
$Var = "Another String"; 
 echo $Var; // Will output "Another String" rather than "test";

所以追加：

$Results_a = ...;
$Results_b = ...;
$Results_c = ...;

因此，您可以轻松处理变量，您可以看到的另一件事是SQL连接：http://dev.mysql.com/doc/refman/5.0/en/join.html以减少单独查询的数量

Answer 2

您需要将查询保存到其他变量：

<?php
include("server_connect.php");

mysql_select_db("rnissen");

$query = "SELECT column_one, column_two, column_four FROM tbltable;"

$results1 = mysql_query($query) or die(mysql_error());

$querytwo = "SELECT column_one, column_two, column_five FROM tbltable WHERE column_five = 1989";

$results2 = mysql_query($querytwo) or die(mysql_error());

$querythree = "SELECT COUNT(column_five) FROM tbltable WHERE column_five = 1989";

$results3 = mysql_query($querythree) or die(mysql_error());

?>

但是，这是使用mysqli_multi_query执行多个查询的更方便的方法：

文档示例：

$query  = "SELECT CURRENT_USER();";
$query .= "SELECT Name FROM City ORDER BY ID LIMIT 20, 5";

/* execute multi query */
if (mysqli_multi_query($link, $query)) {
    do {
        /* store first result set */
        if ($result = mysqli_store_result($link)) {
            while ($row = mysqli_fetch_row($result)) {
                printf("%s\n", $row[0]);
            }
            mysqli_free_result($result);
        }
        /* print divider */
        if (mysqli_more_results($link)) {
            printf("-----------------\n");
        }
    } while (mysqli_next_result($link));
}

编辑：

对于您更新的问题，您在此处缺少分号：

$query = "SELECT column_one, column_two, column_four FROM tbltable";

PHP / MySQL多个查询

2 个答案:

但是，这是使用mysqli_multi_query执行多个查询的更方便的方法：

编辑：