Question

需要迭代以下JSON对象以生成报告（表结构中的表格报告）。

报告基本上由故事列表组成。它的相关任务状态。

QueryResults = {
    "Results": [
        {
            "Name" : "Tech Design",
            "State" : "Completed",
            "StoryName" : "FB Integration"
        },
        {
            "Name" : "Development",
            "State" : "In-Progress",
            "StoryName" : "FB Integration"
        },
        {
            "Name" : "QA Testing",
            "State" : "Not Started",
            "StoryName" : "FB Integration"
        },
        {
            "Name" : "Front End Development",
            "State" : "Completed",
            "StoryName" : "FB Integration"
        },
        {
            "Name" : "Tech Design",
            "State" : "Not Started",
            "StoryName" : "Twitter Integration"
        },
        {
            "Name" : "Development",
            "State" : "Not Started",
            "StoryName" : "Twitter Integration"
        }
    ]
}

HTML填充：

<table>
    <tr>
        <td>StoryName</td>
        <td>TechDesign</td>
        <td>FED</td>
        <td>QA</td>
        <td>Development</td>
    </tr>
    <tr>
        <td>FB Integration</td>
        <td>Completed</td>
        <td>Completed</td>
        <td>In-Progress</td>
        <td>In-Progress</td>
    </tr>
    ......
    ......
</table>

脚本：

for(var i=0; i < QueryResults.Results.length; i++) {
  data+= '<tr><td>' + QueryResults.Results[i].StoryName + '</td><td>' + QueryResults.Results[i].State + '</td></tr>'; 
}

// it will list down all the story name i.e. same story name multiple times

请提供指示，在迭代JSON时删除重复的故事名称，并在其他列中填充相应的详细信息。

Answer 1

您不想删除重复的条目，您希望按故事名称合并它们。

var stories = {};
for (var i=0; i<QueryResults.Results.length; i++) {
    var result = QueryResults.Results[i],
        name = result.StoryName
    if (!(name in stories))
        stories[name] = {};
    stories[name][result.Name] = result.State;
}
/* console.log(stories):
{
    "FB Integration":{"Tech Design":"Completed","Development":"In-Progress","QA Testing":"Not Started","Front End Development":"Completed"},
    "Twitter Integration":{"Tech Design":"Not Started","Development":"Not Started"}
} */

现在你可以从中构建一个表了。

var keys = [];
for (var i=0; i<QueryResults.Results.length; i++) {
    var n = QueryResults.Results[i].Name;
    if (keys.indexOf(n) == -1)
         keys.push(n);
}
var data = "<table><tr><th>Story Name</th>";
for (var i=0; i<keys.length; i++)
    data += "<th>"+keys[i]+"</th>";
data += "</tr>";
for (var storyname in stories) {
    data += "<tr><th>"+storyname+"</th>";
    for (var i=0; i<keys.length; i++)
        data += "<td>"+(stories[storyname][keys[i]] || "n.a.")+"</td>";
    data += "</tr>";
}
data += "</table>";

如果您想确保特定订单或使用自定义表头，您当然也可以使用静态keys数组：

var keys = ["Tech Design","Front End Development","QA Testing","Development"];
var data = "<table><tr><td>StoryName</td><td>TechDesign</td><td>FED</td><td>QA</td><td>Development</td></tr>";
for (storyname in stories) {
…

删除JSON迭代上的重复项

1 个答案: