我正在尝试创建一个minecraft服务器包装器但是我无法读取进程的输出。我想读取serverProcess_ErrorDataRecevied事件中的输出,我知道现在的内容不起作用。但是我可以把它放在那里去阅读呢?
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.Diagnostics;
using System.IO;
namespace MC_Server_UI
{
public partial class Form1 : Form
{
ProcessStartInfo startInfo = new ProcessStartInfo("C:\\Program Files (x86)\\Java\\jre7\\bin\\java.exe", "Xmx1024M - jar " + "craftbukkit.jar" + " nogui");
Process serverProcess;
OpenFileDialog ofd;
FolderBrowserDialog fbd;
public Form1()
{
InitializeComponent();
fbd = new FolderBrowserDialog();
fbd.ShowDialog();
startInfo.WorkingDirectory = fbd.SelectedPath;
startInfo.RedirectStandardInput = startInfo.RedirectStandardError = true;
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
serverProcess = new Process();
serverProcess.StartInfo = startInfo;
serverProcess.EnableRaisingEvents = true;
serverProcess.ErrorDataReceived += new DataReceivedEventHandler(serverProcess_ErrorDataReceived);
serverProcess.Exited += new EventHandler(serverProcess_Exited);
serverProcess.Start();
}
private void serverProcess_ErrorDataReceived(object sender, EventArgs e)
{
richTextBox1.AppendText(serverProcess.StandardError.ReadToEnd());
}
private void serverProcess_Exited(object sender, EventArgs e)
{
}
}
}
答案 0 :(得分:0)
请参阅:
代码:
serverProcess.StartInfo.RedirectStandardOutput = true;
serverProcess.OutputDataReceived += (sender, args) => Console.WriteLine("received output: {0}", args.Data);
serverProcess.Start();
serverProcess.BeginOutputReadLine();
或者:
serverProcess.StartInfo.RedirectStandardOutput = true;
var output = serverProcess.StandardOutput.ReadToEnd();
另请参阅:ProcessStartInfo.RedirectStandardError
serverProcess.StartInfo.RedirectStandardError = true;
var error = serverProcess.StandardError.ReadToEnd();