以下是我从形状[3 4 2]
重塑boost :: multi_array到[12 2]
的代码。由于维度是在boost :: multi_array中修复的,我首先将三维数组重新整形为[12 2 1]
形状,然后将前两个维度复制到一个新数组中。
是否有一种更简单的方法不进行任何复制(我更倾向于以numpy.reshape的精神对原始数据进行查看)。
使用g++ -g test.cc && ./a.out
#include "boost/multi_array.hpp"
#include <cassert>
#include <iostream>
int
main () {
// Create a 3D array that is 3 x 4 x 2
typedef boost::multi_array<double, 3> array_type;
typedef array_type::index index;
array_type A(boost::extents[3][4][2]);
// indexer can be const a boost::array
boost::array<array_type::index,3> idx = {{0,0,0}};
// Assign values to the elements
int values = 0;
for(index i = 0; i != 3; ++i)
for(index j = 0; j != 4; ++j)
for(index k = 0; k != 2; ++k)
A[i][j][k] = values++;
std::cout << "array elements: " << A.num_elements() << std::endl;
std::cout << "array ndim: " << A.num_dimensions() << std::endl;
std::cout << "array size: " << A.size() << std::endl; // equivalent to a.shape()[0];
std::cout << "array shape: " << A.shape()[0] <<" " << A.shape()[1] <<" " << A.shape()[2] << std::endl;
int verify = 0;
for(index i = 0; i != 3; ++i)
for(index j = 0; j != 4; ++j)
for(index k = 0; k != 2; ++k) {
std::cout << "A[" <<i <<"]["<<j<<"]["<<k<<"] = " << A[i][j][k] << std::endl;
assert(A[i][j][k] == verify++);
}
boost::array<array_type::index,3> dims2 = {{12, 2, 1}};
A.reshape(dims2);
std::cout << "array shape: " << A.shape()[0] <<" " << A.shape()[1] <<" " << A.shape()[2] << std::endl;
for(index i = 0; i != 12; ++i)
for(index j = 0; j != 2; ++j)
for(index k = 0; k != 1; ++k) {
std::cout << "A[" <<i <<"]["<<j<<"]["<<k<<"] = " << A[i][j][k] << std::endl;
}
typedef boost::multi_array<double, 2> Array2d;
Array2d B(boost::extents[12][2]);
for(index i = 0; i != 12; ++i)
for(index j = 0; j != 2; ++j){
B[i][j] = A[i][j][0];
std::cout << "B[" <<i <<"]["<<j<<"] = " << B[i][j] << std::endl;
}
return 0;
}
答案 0 :(得分:1)
原来可以通过查看(c.f。Creating Views)来实现这一点。
在我的例子中:
... reshape ...
typedef boost::multi_array_types::index_range range;
array_type::index_gen indices;
array_type::array_view<2>::type myview =
A[ indices[range(0,12)][range(0,2)][0] ];
for(index i = 0; i != 12; ++i)
for(index j = 0; j != 2; ++j){
std::cout << "myview[" <<i <<"]["<<j<<"] = " << myview[i][j] << std::endl;
答案 1 :(得分:1)
我不认为你可以在一般情况下这样做。您可以做的是生成具有较低维度的子视图。我读了你想要让你的2D数组元素与原始3D数组一样多的代码。
您可以做的是使用const_multi_array_ref
重复使用3D数组的现有数据:
boost::multi_array< int, 3 > a( boost::extents[ 2 ][ 3 ][ 4 ] );
boost::const_multi_array_ref< int, 2 > b( a.data(), boost::extents[ 2 ][ 12 ] );
根据存储顺序,这可能会使您尝试获取。
我建议在multi_array
周围编写一个小包装器,使用所需的索引计算访问multi_array
。