Question

我在listview中添加了一个可绘制的图像作为标题。我已经在活动的情况下实现了如下。

listView1 = (ListView)findViewById(R.id.listView1);

    View header = (View)getLayoutInflater().inflate(R.layout.header, null);
    listView1.addHeaderView(header);

但是，现在我试图在像这样的

这样的viewpager片段中实现相同的功能

import android.os.Bundle;
import android.support.v4.app.Fragment;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ListView;

public class ShowFrag1 extends Fragment {
    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container, 
        Bundle savedInstanceState) {
        // Inflate the layout for this fragment
        View v=inflater.inflate(R.layout.frag1, container,false);
        ListView lv1=(ListView) v.findViewById(R.id.listView1);

        Level weather_data[] = new Level[]
                {
                    new Level(R.drawable.s1, "L1", R.drawable.p),
                    new Level(R.drawable.s2, "L2",R.drawable.p),
                    new Level(R.drawable.s3, "L3",R.drawable.p),
                    new Level(R.drawable.s4, "L4",R.drawable.p),
                    new Level(R.drawable.s6, "L5",R.drawable.p)
                };
        LevelAdapter adapter = new LevelAdapter(getActivity(),
                R.layout.list_item, weather_data);

       View header = (View)getLayoutInflater().inflate(R.layout.header, null);
        lv1.addHeaderView(header);

        lv1.setAdapter(adapter);
        return v;
    }
}

现在，我收到一个错误“

Fragment类型中的方法getLayoutInflater（Bundle）不是适用于arguments（）

“在行

View header = (View)getLayoutInflater().inflate(R.layout.header, null);

如何解决此错误？感谢

Answer 1

更改

View header = (View)getLayoutInflater().inflate(R.layout.header, null);

与

  View header = inflater.inflate(R.layout.header, null);

onCreatView的第一个参数是LayoutInflater

Android将片段添加到listview中的标题

1 个答案: