编写一个bash脚本来进行二进制搜索。将学生姓名和成绩从文件读入数组。提示用户输入学生姓名。在数组中找到名称并显示成绩。文件中的数据如下:
Ann:A
Bob:C
Cindy:B
Dean:F
Emily:A
Frank:C
Ginger:D
Hal:B
Ivy:A
Justin:F
Karen:D
我做了以下事情,但我仍然坚持下一步做什么
#!/bin/bash
echo "please enter students Name: "
read student
echo "$student + $Grade"
((i=0))
while read students[$i] ; do
((i++))
done < students.dat
first=0
last=$(students[@])
((mid=0))
Name=`echo ${students[$mid]} | cut -d: -f1`
Grade=`echo ${students[$mid]} | cut -d: -f2`
echo $Name
echo $Grade
答案 0 :(得分:2)
二进制搜索需要搜索的最大和最小边界。从零开始是很好的,但你的最后一个变量有点偏。尝试:last=$(($#students[@]} - 1))
- 1将使您的数组的大小正确(数组从零开始,并减少到它们的大小。)
之后尝试以下伪代码:
while (last is <= first)
middle = midway point between first and last
// make sure that your comparing just the names "Ann",
// not your whole string "Ann:A"
if (students[middle] == student)
exit loop
else if (students[middle] < student)
first = middle + 1
else if (students[middle] > student)
last = middle - 1
我在bash脚本方面不是很出色,所以我不会尝试修复(如果它甚至需要修复)你的大部分语法。如果你弄清楚语法,那么伪代码应该可以帮到你。
答案 1 :(得分:1)
尝试一下,让我得到您的反馈。
#!/bin/bash
##CREATE AN ARRAY VARIABLE TO STORE DATA FOUND IN STUDENT.TXT AT STARTUP
#NAMESARRAY STORE ALL NAMES
declare -a namesarray
#GRADESARRAY STORE ALL GRADES
declare -a gradesarray
#GLOBALMATCHINDEX STORES THE ARRAY INDEX WHERE NAME IS FOUND.... NAMES ARRAY START FROM 0
globalmatchindex=-1
#FUNCTION "CONTAINS" SEARCH THROUGH NAMESARRAY VAIRIABLE TO FIND INPUT FROM USER
function contains(){
#CREATE 2 VARIABLES "e" AND "match"
local e match="$1"
shift
#VARIABLE matchindex IS A LOCAL VARIABLE IN THE "CONTAINS" FUNCTION THAT TEMPORARILY STORES THE VALUE OF THE INDEX WHERE INPUTED NAME IS FOUND IN namesarray VARIABLE
local matchindex=0
#LOOP THROUGH namesarray GLOBAL VARIABLE WHICH WAS PASSED AS A PARAMETER TO THE "CONTAINS" FUNCTION
for e;
do
#CHECK IF A MATCHING STRING IS FOUND IN THE namesarray GLOBAL VARIABLE WHICH WAS PASSED AS A PARAMETER
if [ "$e" == "$match" ]; then
#SET THE VALUE OF globalmatchindex GLOBAL VARIABLE TO THE CURRENT LOOP INDEX ALIAS matchindex
globalmatchindex=$matchindex
#EXIT LOOP AND CONTINUE PROCESS
break
fi
#INCREMENT LOCAL matchindex VARIABLE FOR THE NEXT ROUND OF LOOP
matchindex=$((matchindex+1))
done
}
#FUNCTION "CONTAINS" END HERE
#linenumber GLOBAL VARIABLE STORES THE CURRENT LINE NUMBER IN students.txt FILE
linenumber=0
#A LOOP THAT READ ENTIRE student.txt FILE
while read line; do
#SINCE THE NAMES AND GRADES ARE SEPARATED BY ":" CHARACTER, WE USE A STRING SPLIT METHOD TO SEPARATE NAME FROM GRADE
IFS=':'
#READ EACH LINE AS ARRAY TO "LINEARRAY" VARIABLE. "LINEARRAY" VARIABLE CONTAINS CONTENT LIKE SO "LINEARRAY[0]='JAMES'", "LINEARRAY[1]='A'"
read -ra LINEARRAY <<< "$line"
#STORE THE FIRST STRING IN namesarray GLOBAL VARIABLE
namesarray[$linenumber]=${LINEARRAY[0]}
#STORE THE SECOND STRING IN gradesarray GLOBAL VARIABLE
gradesarray[$linenumber]=${LINEARRAY[1]}
linenumber=$((linenumber+1))
done < students.txt
while true; do
echo "Enter Student name:"
read studentname
contains "$studentname" "${namesarray[@]}"
if [ $globalmatchindex -gt -1 ]; then
echo "Hello ${namesarray[$globalmatchindex]} your grade is ${gradesarray[$globalmatchindex]}"
else
echo "Student not found."
fi
globalmatchindex=-1
done
student.txt文件的内容如下。
Ann:A
Bob:C
Cindy:B
Dean:F
Emily:A
Frank:C
Ginger:D
Hal:B
Ivy:A
Justin:F
Karen:D
答案 2 :(得分:0)
我认为最好使用通用二进制搜索功能,然后为您的特定情况编写自己的代码。
# Returns the largest i for which `command i` succeeds (exits with a null exit code)
function dichotomic_search {
min=$1
max=$2
command=$3
while [ $min -lt $max ]; do
# Compute the mean between min and max, rounded up to the superior unit
current=`expr '(' "$min" + "$max" + 1 ')' / 2`
if $command $current
then min=$current
else max=`expr $current - 1`
fi
done
echo $min
}
它使用二进制搜索重复调用给定的函数作为其最后一个参数,以查找返回true的最后一个值。 More explanations on Github
在你的情况下,你会像那样使用它:
#!/usr/bin/env bash
source dichotomic.sh
arr=(Ann:C Bob:A Cindy:B Dean:E Emily:A Karen:A Zob:A)
function is_smaller {
element=$(echo ${arr[$2]} | cut -f1 -d :)
if [[ "$element" > "$1" ]]
then false
else true
fi
}
read target
highest_index=`expr ${#arr[@]} - 1`
index=$(dichotomic_search 0 $highest_index "is_smaller $target")
echo "${arr[$index]}"
答案 3 :(得分:0)
此解决方案假设您正在寻找第一个成功执行命令,而不是数组中的元素。
lo=1
hi=100
while [ $(expr $hi - $lo) -ne 1 ]; do
mid=$(expr $lo + '(' $hi - $lo ')' / 2)
# Your command here
test 44 -gt $mid
if [ $? -eq 0 ]; then lo=$mid; else hi=$mid; fi
done
echo "$lo"
这总是打印执行命令成功的 first 值,而不像@lovasoa解决方案在大约一半配置中关闭一个。您可以使用seq 1 100 | while read o; do SCRIPT; done
验证这一点,其中SCRIPT
是上述算法test $o -gt $mid
作为测试命令。