{
"entries": [
{
"id": 23931763,
"url": "http://www.dailymile.com/entries/23931763",
"at": "2013-07-15T21:05:39Z",
"message": "I ran 3 miles and walked 2 miles today.",
"comments": [],
"likes": [],
"user": {
"username": "DeanaLaughli",
"display_name": "Deana O.",
"photo_url": "http://s3.dmimg.com/pictures/users/361413/1329826045_avatar.jpg",
"url": "http://www.dailymile.com/people/DeanaLaughli"
},
"workout": {
"activity_type": "Fitness",
"distance": {
"value": 5,
"units": "miles"
},
"felt": "great"
}
},
{
"id": 23931680,
"url": "http://www.dailymile.com/entries/23931680",
"at": "2013-07-15T21:01:03Z",
"message": "More strength training",
"comments": [],
"likes": [],
"location": {
"name": "MA"
},
"user": {
"username": "Ecm2571",
"display_name": "Eileen",
"photo_url": "http://s3.dmimg.com/pictures/users/323833/1368556483_avatar.jpg",
"url": "http://www.dailymile.com/people/Ecm2571"
},
"workout": {
"activity_type": "Weights",
"title": "Upper and lower body "
}
}
]
}
以下是我通过URL中的JSONP请求获取的JSON数组的示例。我想显示:
但是,正如您在数组中看到的那样,有时不会给出此信息,当发生这种情况时,代码会停止加载更多条目。当没有要加载的数据时,我需要一种显示空格的方法。这是我的代码,感谢您的帮助。
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"> </script>
<script>
$(function() {
var entries = [];
var workout.activity
var dmJSON = "http://api.dailymile.com/entries.json?callback=?";
$.getJSON( dmJSON, function(data) {
$.each(data.entries, function(i, f) {
var tblRow = "<tr>" +
"<td><img src=" + f.user.photo_url + "></td>" +
"<td>" + f.user.username + "</td>" +
"<td>" + f.message + "</td>" +
//"<td>" + f.location.name + "</td>" +
"<td>" + f.workout.activity_type + "</td>" +
"<td>" + f.workout.duration + "</td>" +
"<td>" + f.workout.distance.value + f.workout.distance.units + "</td>" +
"</tr>"
$(tblRow).appendTo("#entrydata tbody");
});
});
});
</script>
</head>
<body>
<div class="wrapper">
<div class="profile">
<table id= "entrydata" border="1">
<thead>
<th></th>
<th>Username</th>
<th>Message</th>
<th>Exercise Type</th>
<th>Duration</th>
<th>Distance</th>
</thead>
<tbody>
</tbody>
</table>
</div>
</div>
</body>
</html>
答案 0 :(得分:2)
首先在chrome中运行它并打开Web工具。 一旦出现“达到”错误,您将在控制台日志中看到错误。
您的问题是您尝试读取未定义的值。 您可以通过在尝试从中读取任何值之前检查每个对象来解决它,或者使用在缺少某个值时返回默认值的函数。
以下是完整的工作代码:
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script>
/**
* Extract the property formthe object.
* If teh property not found it will return empty string
*/
function getProperty(object, property) {
if (!property) {
return '';
}
var
// Break the property to its nested properties
properties = property && property.split('.'),
// the current object that we want to extract the property from
current = object,
index;
// Loop over the properties and process them
for (index = 0; index < properties.length; index++) {
property = properties[index];
// Check to see that there is a property with the given name
if (current.hasOwnProperty(property)) {
current = current[property];
} else {
return '... N/A ...';
}
}
// If we got so far it means the the 'current' contain the needed value
return current;
}
$(function () {
var entries = [],
dmJSON = "http://api.dailymile.com/entries.json?callback=?";
$.getJSON(dmJSON, function (data) {
$.each(data.entries, function (i, f) {
var tblRow = "<tr>" +
"<td><img src=" + getProperty(f, 'user.photo_url') + "></td>" +
"<td>" + getProperty(f, 'user.username') + "</td>" +
"<td>" + getProperty(f, 'message') + "</td>" +
//"<td>" + f.location.name + "</td>" +
"<td>" + getProperty(f, 'workout.activity_type') + "</td>" +
"<td>" + getProperty(f, 'workout.duration') + "</td>" +
"<td>" + getProperty(f, 'workout.distance.value') + getProperty(f, 'workout.distance.units') + "</td>" +
"</tr>";
$(tblRow).appendTo("#entrydata tbody");
});
});
});
</script>
</head>
<body>
<div class="wrapper">
<div class="profile">
<table id="entrydata" border="1">
<thead>
<th></th>
<th>Username</th>
<th>Message</th>
<th>Exercise Type</th>
<th>Duration</th>
<th>Distance</th>
</thead>
<tbody>
</tbody>
</table>
</div>
</div>
</body>
</html>