在java中是否有一个命令使程序回到循环的开头

时间:2013-07-15 18:07:10

标签: java loops command switch-statement

我正在尝试在java中进行打字冒险游戏,但是我需要一个至少类似于标题中的命令的命令,这里是代码

import java.util.Scanner;

public class MyFirstGameInJava {

public static void main(String[] args) {

System.out.println("Greetings, Enter your name and you may start your quest!");
Scanner Username = new Scanner(System.in);
String name = Username.nextLine();
System.out.println("Greetings " + name );
System.out.println("Welcome to an Unnamed Typing Advanture");
System.out.println("You find yourself on an island with very few trees, you can either hit a tree, or walk along");

String sc = Username.nextLine();

switch(sc){

case "Hit tree":
System.out.println("A coconut falls from the tree");
System.out.println("You can either eat the coconut or throw it");
break;
case "Walk":
System.out.println("You walk for a mile and find a village");
System.out.println("The village appears empty, you can either scream to see if anybody is there, or you can keep walking");
break;
default :
System.out.println("Nothing happens...");
}   

String sc1 = Username.nextLine();


switch(sc1){

case "Eat coconut":
System.out.println("You ate the coconut and got poisoned");
System.out.println("You died...");
break;
case "Throw coconut":
System.out.println("By throwing the coconut, you awaken a tiger and he eats you");
System.out.println("You are dead");
break;
case "Scream":
System.out.println("As soon as you scream, a man shoots you down from a window from one of the houses");
System.out.println("You died...");
break;
case "Walk":
System.out.println("You walked through the village, and you find a boat and leave the island");
System.out.println("You win! Updates coming soon!");
break;
default:
System.out.print("Nothing happend");



}

}

}

每当用户键入除了需要之外的其他内容时,就会出现默认情况,但我需要它返回到循环的开头,因此用户可以键入其他一种情况。

5 个答案:

答案 0 :(得分:6)

您可以使用continue语句继续下一次迭代。

那就是说,我在示例代码中看不到循环。您可以使用forwhiledo/while进行循环播放。 do/while循环至少执行一次 - 这通常是在向用户询问问题时要执行的操作。

Java tutorial for Branching Statementscontinue循环中提供了for语句的示例。

   for (int i = 0; i < max; i++) {
        // interested only in p's
        if (searchMe.charAt(i) != 'p')
            continue;

        // process p's
        numPs++;
    }

答案 1 :(得分:3)

continue;与无条件循环一起使用,例如

while(true){/* your code*/}

答案 2 :(得分:0)

您的问题做出了错误的假设。 switch()语句不是循环。它是一堆if / else-if语句的简写:

if(sc1.equals("Eat coconut")) {
    System.out.println("You ate the coconut and got poisoned");
    System.out.println("You died...");
}
else if(sc1.equals("Throw coconut")) {
//and so on

要做你想做的事,你需要一个实际的while()for()循环。 (这些链接将带您阅读解释这两种结构的Java教程。)

答案 3 :(得分:0)

我的CS课也有同样的问题:这就是我做的。首先,您需要使用循环。我使用了'while'循环。

所以说你正处于对话的某个阶段,有人要求其他人(比如武术大师要求玩家)做某事,答案选择是“y”或“n”。但玩家输入“m”。这会产生错误。要修复它,您需要创建一个(循环)来继续检查用户是否键入了有效响应,并相应地继续该程序。现在代码......

//Ask if they want to see the rules.    
System.out.println("Welcome Player One");  
System.out.println("Would you like to read the rules of the gem?");  
System.out.println("[y]Yes, please / [n]I know the rules."); //So you made it clear that the choices are 'y' or 'n' (yes or no).

//Decide if they hit yes or no.  
char Response; //Variable to hold user response.  
Scanner Console = new Scanner(System.in); //I don't know why, exactly, but you need this.  
Response = Console.next().charAt(0); //Set response to the user input. A input field will appear.  
while(true){  //Making the parameter 'true' makes the flow of the loop depend on the parameters in the if statements (I think).  
  if(Response == 'y' || Response == 'Y'){  
   System.out.println("Here are the rules:");  
   break; //break will make the flow exit the while loop (so you can continue adding the rest of your code).  
  }  
  else if(Response == 'n' || Response == 'N'){  
   System.out.println("Then let us continue:");  
   break;  
  }  
  else{  
   System.out.println("Would you like to read the rules of the gem?"  
   System.out.println("You have to enter (y)yes or (n)no...");  
   Response = Console.next().charAt(0); //Just like before, input field will  appear to give them the chance to change their response to a valid one.  
   continue; //This has to be 'continue' so that the loop will continue to "check" for the value that needs to be input by the user.  
  }  
}

希望这会有所帮助,欢呼。

答案 4 :(得分:0)

不那么详细,更直接。我已经解释了简单的答案。

for(int i = 0; i <= 10; i++){
        if(i == 4){
            continue;
        }
        //Should skip 4 and print out 1,2,3,5,6,7,8,9,10
        System.out.println(i);
    }