Question

我正在尝试从我正在开发的API上运行的一组测试中捕获异常，并且我使用Guzzle来使用API方法。我已经将测试包装在try / catch块中，但它仍然会抛出未处理的异常错误。按照文档中的描述添加事件侦听器似乎没有做任何事情。我需要能够检索具有500,401,400的HTTP代码的响应，实际上任何不是200的响应，因为如果系统不起作用，系统将根据调用的结果设置最合适的代码

当前代码示例

foreach($tests as $test){

        $client = new Client($api_url);
        $client->getEventDispatcher()->addListener('request.error', function(Event $event) {        

            if ($event['response']->getStatusCode() == 401) {
                $newResponse = new Response($event['response']->getStatusCode());
                $event['response'] = $newResponse;
                $event->stopPropagation();
            }            
        });

        try {

            $client->setDefaultOption('query', $query_string);
            $request = $client->get($api_version . $test['method'], array(), isset($test['query'])?$test['query']:array());


          // Do something with Guzzle.
            $response = $request->send();   
            displayTest($request, $response);
        }
        catch (Guzzle\Http\Exception\ClientErrorResponseException $e) {

            $req = $e->getRequest();
            $resp =$e->getResponse();
            displayTest($req,$resp);
        }
        catch (Guzzle\Http\Exception\ServerErrorResponseException $e) {

            $req = $e->getRequest();
            $resp =$e->getResponse();
            displayTest($req,$resp);
        }
        catch (Guzzle\Http\Exception\BadResponseException $e) {

            $req = $e->getRequest();
            $resp =$e->getResponse();
            displayTest($req,$resp);
        }
        catch( Exception $e){
            echo "AGH!";
        }

        unset($client);
        $client=null;

    }

即使使用抛出的异常类型的特定catch块，我仍然会回来

Fatal error: Uncaught exception 'Guzzle\Http\Exception\ClientErrorResponseException' with message 'Client error response [status code] 401 [reason phrase] Unauthorized [url]

并且页面上的所有执行都会停止，正如您所期望的那样。添加BadResponseException捕获允许我正确捕获404，但这似乎不适用于500或401响应。任何人都可以建议我哪里出错了。

Answer 1

根据您的项目，可能需要禁用guzzle的例外情况。有时编码规则不允许流控制的异常。你可以禁用例如 for Guzzle 3 ：

$client = new \Guzzle\Http\Client($httpBase, array(
  'request.options' => array(
     'exceptions' => false,
   )
));

这不会禁用超时之类的卷曲异常，但现在您可以轻松获取每个状态代码：

$request = $client->get($uri);
$response = $request->send();
$statuscode = $response->getStatusCode();

要检查，如果你有一个有效的代码，你可以使用这样的东西：

if ($statuscode > 300) {
  // Do some error handling
}

...或更好地处理所有预期的代码：

if (200 === $statuscode) {
  // Do something
}
elseif (304 === $statuscode) {
  // Nothing to do
}
elseif (404 === $statuscode) {
  // Clean up DB or something like this
}
else {
  throw new MyException("Invalid response from api...");
}

对于Guzzle 5.3

$client = new \GuzzleHttp\Client(['defaults' => [ 'exceptions' => false ]] );

感谢@mika

Guzzle 6

$client = new \GuzzleHttp\Client(['http_errors' => false]);

Answer 2

要捕捉Guzzle错误，您可以执行以下操作：

try {
    $response = $client->get('/not_found.xml')->send();
} catch (Guzzle\Http\Exception\BadResponseException $e) {
    echo 'Uh oh! ' . $e->getMessage();
}

...但是，为了能够“记录”或“重新发送”您的请求，请尝试以下方法：

// Add custom error handling to any request created by this client
$client->getEventDispatcher()->addListener(
    'request.error', 
    function(Event $event) {

        //write log here ...

        if ($event['response']->getStatusCode() == 401) {

            // create new token and resend your request...
            $newRequest = $event['request']->clone();
            $newRequest->setHeader('X-Auth-Header', MyApplication::getNewAuthToken());
            $newResponse = $newRequest->send();

            // Set the response object of the request without firing more events
            $event['response'] = $newResponse;

            // You can also change the response and fire the normal chain of
            // events by calling $event['request']->setResponse($newResponse);

            // Stop other events from firing when you override 401 responses
            $event->stopPropagation();
        }

});

...或者如果你想“停止事件传播”，你可以覆盖事件监听器（优先级高于-255）并简单地停止事件传播。

$client->getEventDispatcher()->addListener('request.error', function(Event $event) {
if ($event['response']->getStatusCode() != 200) {
        // Stop other events from firing when you get stytus-code != 200
        $event->stopPropagation();
    }
});

这是一个好主意，可以防止像guzzle错误：

request.CRITICAL: Uncaught PHP Exception Guzzle\Http\Exception\ClientErrorResponseException: "Client error response

在您的申请中。

Answer 3

在我的情况下，我在命名空间文件上抛出Exception，因此php试图捕获My\Namespace\Exception因此根本没有捕获任何异常。

值得检查catch (Exception $e)是否找到了正确的Exception课程。

只需尝试catch (\Exception $e)（那里有\），看看它是否有效。

Answer 4

如果在try块中抛出了异常，那么在最坏的情况下，Exception应捕获任何未捕获的内容。

考虑测试的第一部分是抛出异常并将其包装在try块中。

Answer 5

您需要使用http_errors =＆gt;添加额外参数假

$request = $client->get($url, ['http_errors' => false]);

Answer 6

旧问题，但Guzzle在异常对象中添加了响应。所以GuzzleHttp\Exception\ClientException上的一个简单的try-catch然后在该异常上使用getResponse来查看400级错误并从那里继续。

Answer 7

正如@dado建议的那样，我抓住了GuzzleHttp\Exception\BadResponseException。但有一天，当域名DNS不可用时，我得到了GuzzleHttp\Exception\ConnectException。所以我的建议是 - 抓住GuzzleHttp\Exception\ConnectException以确保DNS错误的安全。

Answer 8

我想更新Psr-7 Guzzle，Guzzle7和HTTPClient（laravel提供的Guzzle HTTP客户端周围的表达，最小的API）中异常处理的答案。

Guzzle7（与Guzzle 6相同）

使用RequestException ，RequestException捕获在传输请求时可能引发的任何异常。

try{
  $client = new \GuzzleHttp\Client(['headers' => ['Authorization' => 'Bearer ' . $token]]);
  
  $guzzleResponse = $client->get('/foobar');
  // or can use
  // $guzzleResponse = $client->request('GET', '/foobar')
    if ($guzzleResponse->getStatusCode() == 200) {
         $response = json_decode($guzzleResponse->getBody(),true);
         //perform your action with $response 
    } 
}
catch(\GuzzleHttp\Exception\RequestException $e){
   // you can catch here 400 response errors and 500 response errors
   // You can either use logs here use Illuminate\Support\Facades\Log;
   $error['error'] = $e->getMessage();
   $error['request'] = $e->getRequest();
   if($e->hasResponse()){
       if ($e->getResponse()->getStatusCode() == '400'){
           $error['response'] = $e->getResponse(); 
       }
   }
   Log::error('Error occurred in get request.', ['error' => $error]);
}catch(Exception $e){
   //other errors 
}

Psr7食尸鬼

use GuzzleHttp\Psr7;
use GuzzleHttp\Exception\RequestException;

try {
    $client->request('GET', '/foo');
} catch (RequestException $e) {
    $error['error'] = $e->getMessage();
    $error['request'] = Psr7\Message::toString($e->getRequest());
    if ($e->hasResponse()) {
        $error['response'] = Psr7\Message::toString($e->getResponse());
    }
    Log::error('Error occurred in get request.', ['error' => $error]);
}

对于HTTPClient

use Illuminate\Support\Facades\Http;
try{
    $response = Http::get('http://api.foo.com');
    if($response->successful()){
        $reply = $response->json();
    }
    if($response->failed()){
        if($response->clientError()){
            //catch all 400 exceptions
            Log::debug('client Error occurred in get request.');
            $response->throw();
        }
        if($response->serverError()){
            //catch all 500 exceptions
            Log::debug('server Error occurred in get request.');
            $response->throw();
        }
        
    }
 }catch(Exception $e){
     //catch the exception here
 }

Answer 9

.items-holder
{
    background-color: #E7E7E7;
    border-radius: 4px;
    padding: 10px;
    display: inline-block;
    border-collapse: separate;
    border-spacing: 10px 0px;
    vertical-align:middle;
}

从Guzzle中获取异常

9 个答案:

Guzzle7（与Guzzle 6相同）

Psr7食尸鬼

对于HTTPClient