Question

您好我正在使用api但是我应该为它做一个补丁

Songapi.prototype.goPlaySong=Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false');

不起作用也尝试了

Songapi.prototype.goPlaySong=Function(Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false'));

或

Songapi.prototype.goPlaySong=eval(Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false'));

仍然无法做到这一点？

Answer 1

DEMO

SongApi是constructor a.k.a一个班级。

function inherits(child, parent) {
  function temp() {};
  temp.prototype = parent.prototype;
  child.prototype = new temp();
  child.prototype.constructor = child;
};

var CustomizedApi = function() {
    SongApi.call(this);
};
inherits(CustomizedApi, Songapi);
// or use Object.create for inheritance.
CustomizedApi.prototype = Object.create(SongApi.prototype);

/**
 * @override
 */
CustomizedApi.prototype.goPlaySong = function() {
   // override with whatever you want.
};
var api = new CustomizedApi;
api.goPlaySong();

Answer 2

尝试：

eval('var code = ' + Songapi.prototype.goPlaySong.toString().replace('["universal","emi","warner"]) !== -1','false'));

Songapi.prototype.goPlaySong = code;

但这绝对是肮脏的。

Answer 3

var newgoPlaySong=Songapi.prototype.goPlaySong.toString().replace('$.inArray(response.provider,["universal","emi","warner"]) !== -1','false');
eval('Songapi.prototype.goPlaySong = '+gecicigoPlaySong+';');

感谢

如何编辑js对象/函数

3 个答案: