Question

我正在XAMMP中使用PHP ang MySQL或PhpMyAdmin创建一个选美评分系统。在查询时我不是专家。所以我真的不知道该做什么，或者如何根据他们在有5名评委和9名候选人的类别中的分数来获得候选人的排名。

这是我的数据库...希望有人可以帮助我使用查询获得排名。提前谢谢。

CREATE TABLE IF NOT EXISTS score (
 candidate_no varchar(5) NOT NULL  ,
 category_no varchar(5) NOT NULL  ,
 judge_id varchar(5) NOT NULL  ,
 score int(3),
 PRIMARY KEY (candidate_no,category_no,judge_id),
 KEY score_fkey (judge_id),
 KEY score_fkey3 (category_no)) ;



INSERT INTO  score  (candidate_no,  category_no,  judge_id,  score) VALUES
('C1', 'cat1', 'J1', 17),
('C1', 'cat1', 'J2', 15),
('C1', 'cat1', 'J3', 17),
('C1', 'cat1', 'J4', 18),
('C1', 'cat1', 'J5', 19),
('C2', 'cat1', 'J1', 17  ),
('C2', 'cat1', 'J2', 15  ),
('C2', 'cat1', 'J3', 16  ),
('C2', 'cat1', 'J4', 18  ),
('C2', 'cat1', 'J5', 18  ),
('C3', 'cat1', 'J1', 15  ),
('C3', 'cat1', 'J2', 20  ),
('C3', 'cat1', 'J3', 19  ),
('C3', 'cat1', 'J4', 16  ),
('C3', 'cat1', 'J5', 19  ),
('C4', 'cat1', 'J1', 19 ),
('C4', 'cat1', 'J2', 20  ),
('C4', 'cat1', 'J3', 18  ),
('C4', 'cat1', 'J4', 18  ),
('C4', 'cat1', 'J5', 19  ),
('C5', 'cat1', 'J1', 18  ),
('C5', 'cat1', 'J2', 16 ),
('C5', 'cat1', 'J3', 18  ),
('C5', 'cat1', 'J4', 18  ),
('C5', 'cat1', 'J5', 18  ),
('C6', 'cat1', 'J1', 20  ),
('C6', 'cat1', 'J2', 16 ),
('C6', 'cat1', 'J3', 16  ),
('C6', 'cat1', 'J4', 16  ),
('C6', 'cat1', 'J5', 17  ),
('C7', 'cat1', 'J1', 11 ),
('C7', 'cat1', 'J2', 12  ),
('C7', 'cat1', 'J3', 14  ),
('C7', 'cat1', 'J4', 15  ),
('C7', 'cat1', 'J5', 17  ),
('C8', 'cat1', 'J1', 15  ),
('C8', 'cat1', 'J2', 16  ),
('C8', 'cat1', 'J3', 18  ),
('C8', 'cat1', 'J4', 17 ),
('C8', 'cat1', 'J5', 17  ),
('C9', 'cat1', 'J1', 19  ),
('C9', 'cat1', 'J2', 19  ),
('C9', 'cat1', 'J3', 19  ),
('C9', 'cat1', 'J4', 19  ),
('C9', 'cat1', 'J5', 18  );

Answer 1

尝试在SQL查询开头添加此内容

SET @rank=0; SELECT @rank:=@rank+1 AS rank, //rest of the query goes here

如何在mysql中获得Rank？

1 个答案: