我必须使用未定义的列创建一个基于Json数据的网格
[{
Name: "John",
Designation: "Analyst",
Age: 25,
Department: "IT"
},
{
Name: "Matthew",
Designation: "Manager",
Age: 38,
Department: "Accounts"
},
{
Name: "Emma",
Designation: "Senior Manager",
Age: 40,
Department: "HR"
}];
我想要的输出如下:
标题:
Name | Designation | Age | Department
as datarow:
John | Analyst | 25 | IT
请有人帮助我如何开始以及如何做。
答案 0 :(得分:0)
重复问题How to put JSON data in html / javascript grid table [如果您在发布前检查]
这是数据表 - http://datatables.net/release-datatables/examples/data_sources/js_array.html
这是网格表JS - http://backgridjs.com/#examples
答案 1 :(得分:0)
$.each(Jsonstring,function(){
alert(JsonString.Name);
alert(JsonString.Designation)
alert(JsonString.Age)
alert(JsonString.Department)
});
答案 2 :(得分:0)
这里我已经迭代并以表格格式显示数据这是您正在寻找的Fiddle Demo
$table = "<table id = 'resultTable' border=1>";
$.each(data[0] , function(key, value){
$table += "<td>"+key+"</td>";
});
$table += "<tr>";
for (var i = 0; i < data.length; i++) {
$table += "<tr>";
var it = data[i];
$table += "<td>" + data[i].Name + "</td>";
$table += "<td>" + data[i].Designation + "</td>";
$table += "<td>" + data[i].Age + "</td>";
$table += "<td>" + data[i].Department + "</td>";
//alert(items[i].duration);
$table += "</tr>";
}
$table += "</table>";
$('body').append($table);
答案 3 :(得分:0)
for ... in循环将完全按照您的需要进行操作。
以下是Mozilla开发者网络撰写的内容: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for...in
在“for ... in循环”中,测试属性是否具有指定的属性并且不继承此属性至关重要。(hasOwnProperty)
工作示例:http://jsbin.com/ecoqax/1/edit
我在这里使用jQuery:
var $theader = $("thead"),
$tbody = $("tbody"),
hasHeader = false,
html = "";
// data is the converted JSON data
for (var i = 0; i < data.length; i++) {
// the current person
var person = data[i];
html += '<tr>';
// iterating over every property of the person object
for (var prop in person) {
if (person.hasOwnProperty(prop)) {
// insert the header once
if (hasHeader === false) {
$theader.append($('<th>'+prop+'</th>'));
}
html += '<td>'+person[prop]+'</td>';
}
}
// after the first iteration the header is added
hasHeader = true;
html += '</tr>';
}
$tbody.append($(html));