我认为这可能是一个死锁问题,但我只是在阅读表数据。或者我看不到的非常简单的东西。
我的$msqli
obj适用于数据库访问
但我对这个错误感到有点难过..
我被告知clients
表未被LOCK TABLES
欢迎任何建议..谢谢 这是我的PHP代码
$mysqli = $GLOBALS['mysqli'];
$mysqli->query("LOCK TABLES clients READ, invoices READ, estimates READ");
$mysqli->query("SET @inv='Invoice'");
$mysqli->query("SET @est='Estimate'");
$sql = " (SELECT @inv, name AS client, invoices.id, invoices.ref AS ref, invoices.addTs AS ts \n"
. "FROM `clients` , `invoices` \n"
. "WHERE invoices.user_id = " . $_SESSION['user_id'] . " \n"
. "AND clients.id = invoices.client_id)\n"
. "UNION ALL\n"
. "(SELECT @est, name as client, estimates.id, estimates.ref AS ref, estimates.addTs AS ts \n"
. "FROM `clients` ,`estimates` \n"
. "WHERE estimates.user_id = " . $_SESSION['user_id'] . " \n"
. "AND clients.id = estimates.client_id) \n"
. "ORDER BY ts DESC LIMIT 5";
if ($result = $mysqli->query($sql) or die(mysqli_error($mysqli))) {
//Do stuff here
}
当我在PhpMyAdmin中运行此$sql
查询时,它成功了...
谢谢你的帮助..
的 的 ** * ** * ** * 的** * ** * ** * ** 已解决(?) 的 ** * ** * ** * ** * ** < EM> * ** *
已修复(或似乎是):
来自http://bugs.mysql.com/bug.php?id=6588
“你不能在一个查询中多次使用锁定表 - 为此使用别名。”
因此查询更新为
$mysqli->query("LOCK TABLES clients_t READ,clients READ ,
invoices READ, estimates READ");
$mysqli->query("SET @inv='Invoice'");
$mysqli->query("SET @est='Estimate'");
$sql = " " .
"(SELECT @inv, name AS client, invoices.id,
invoices.ref AS ref, invoices.addTs AS ts "
. "FROM `clients` AS clients_t , `invoices`\n"
. "WHERE invoices.user_id = " . $_SESSION['user_id'] . " \n"
. "AND clients_t.id = invoices.client_id)\n"
. "UNION ALL \n"
. "(SELECT @est , name AS client, estimates.id,
estimates.ref AS ref, estimates.addTs AS ts\n"
. "FROM `clients` ,`estimates` \n"
. "WHERE estimates.user_id = " . $_SESSION['user_id'] . " \n"
. "AND clients.id = estimates.client_id)\n"
. "ORDER BY ts DESC LIMIT 5";
我还需要锁定别名表clients_t
。
无论如何对于未来的用户我希望这会有所帮助
答案 0 :(得分:0)
有点挑剔,但对于$ _SESSION [&#39; user_id&#39;]输入执行诸如addslashes或mysql_real_escape_string之类的操作是明智的,以避免注入问题。