Question

我正在创建一个表，每行都有一个按钮删除，它应该删除该行。但是，现在，当我点击删除时，＆＃34;没有任何反应＆＃34;我必须刷新页面才能看到结果。请帮助。

我的代码index.php

<body>

    <?php include "include/connect.php"; ?>

    <table>
        <tr>
            <th>ID</th>
            <th>First Name</th>
            <th>Last Name</th>
            <th>Proffesion</th>
            <th>Rank</th>
            <th>Options</th>
            <th>&nbsp;</th>
        </tr>
        <tr>
            <form action="add.php" method="post">
                <td><input type="text" name="id" disabled size="5"></td>
                <td><input type="text" name="fname"></td>
                <td><input type="text" name="lname"></td>
                <td><input type="text" name="prof"></td>
                <td><input type="text" name="rank" size="5"></td>
                <td><input type="submit" value="add" name="watta"></td>
                <td>&nbsp;</td>
            </form>
        </tr>

        <?php
            $query = "SELECT * FROM staff";
            $vysledek = mysqli_query($link, $query);

            while ($udaj = mysqli_fetch_array($vysledek)):

                if($udaj[4]==0){
                    echo "<tr class='zero'>";
                } else {
                    echo "<tr>";    
                }



                echo "<td>" . $udaj[0] . "</td>";
                echo "<td>" . $udaj[1] . "</td>";
                echo "<td>" . $udaj[2] . "</td>";
                echo "<td>" . $udaj[3] . "</td>";
                echo "<td>" . $udaj[4] . "</td>";
                echo "<td class='btn'><a href=''>";

                ?>
                <form action="delete.php" method="get">
                    <input name="id" type="hidden" value="<?php echo $udaj[0]; ?>">
                    <input name="what" type="submit" value="DELETE">
                </form>

                <?php
                echo "</a></td>";
                echo "<td class='btn'><a href=''>edit</a></td>";

                echo "</tr>";

            endwhile;


        ?>

    </table>

</body>

delete.php

<?php

include "include/connect.php";

$toId = ($_GET["id"]);

$queryy = "DELETE FROM staff WHERE id=$toId";
$vysledek = mysqli_query($link, $queryy);

header('Location: http://www.w3dominik.com/x/phptest/');

connect.php

<?php

include "config.php";

$link = mysqli_connect(SQL_HOST, SQL_USERNAME, SQL_PASSWORD, SQL_DBNAME);
mysqli_set_charset($link, "utf8");

if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}

http://www.w3dominik.com/x/phptest/

的现场演示

Answer 1

查看connect.php并确保没有输出。如果在它之前输出任何空格或空行，header()将无效。很容易错误地输入某种空白字符。 http://php.net/manual/en/function.header.php

php从<table> </table>删除mySQL行

1 个答案: