这可能是ios-armv7的llvm-gcc的错误,我无法解释

时间:2013-07-14 07:34:06

标签: ios c gcc arm

    the following code works fine on linux-x86, darwin-x86, but not for ios-armv7.

    the right output should be: 
        m[0]: 0.500000, v: 0.500000
        m[1]: 0.500000, v: 0.500000
        m[2]: 0.500000, v: 0.500000
        m[3]: 0.500000, v: 0.500000
        m[4]: 0.500000, v: 0.500000

    but I found the wrong output:
        m[0]: 0.500000, v: 0.500000
        m[1]: 0.500000, v: 0.000000
        m[2]: 0.500000, v: 0.000000
        m[3]: 0.500000, v: 0.000000
        m[4]: 0.500000, v: 0.000000

    I also found the stange when it's built for ios-armv7:

    [a] remove function 'func', move the function body to 'main' function, it works fine
    [b] declare the array 'm[5]' as 'double m[5]', it works fine
    [c] set the variable 'v' as 'v = 0.5 or v = sqrt(2.0f/8)', it works fine
    [d] if the gcc optimize option is '-O0', it works fine, but when it's '-O1 or -O2', wrong output occurs


    My iPad1 was cracked, so I can cross-compile a executable on my MacBook Air, and 'scp' the executable to iPad1 and run it. The following is details:

    1. cross-compile a executable on Mac:
    /Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/usr/bin/llvm-gcc -O1 -Wall -arch armv7 -mcpu=cortex-a8 -isysroot /Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk -I/Applications/Xcode.app/Contents/Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS6.1.sdk/usr/include -D__IPHONE_OS__ -miphoneos-version-min=4.0 foo.c

    2. 'scp' the executable to iPad
    scp a.out mobile@192.168.1.106:~

    3. 'ssh' to iPad
    ssh mobile@192.168.1.106 #the default password is 'alpine'

    4. run a.out on iPad
    ./a.out
#include <stdio.h>
#include <math.h>

int
func(int n) /* [a] */
{
    int i;
    float m[5]; /* [b] */
    double v;

    v = sqrt(2.0f/n); /* [c] */

    for(i=0;i<5;++i) {
        m[i]=v;
        printf("m[%d]: %f, v: %f\n", i, m[i], v);
    }

    return 0;
}


int
main(int argc, char **argv)
{
    return func(8);
}

您还可以在https://gist.github.com/ashun/5992120

上找到整个代码

以下是装配。你可以在命令'vim -d'

的帮助下找到差异
  1. 汇编前面的代码,将数组'm [5]'声明为'double m [5]'
  2.         .section    __TEXT,__text,regular,pure_instructions
            .section    __TEXT,__textcoal_nt,coalesced,pure_instructions
            .section    __TEXT,__const_coal,coalesced
            .section    __TEXT,__picsymbolstub4,symbol_stubs,none,16
            .section    __TEXT,__StaticInit,regular,pure_instructions
            .syntax unified
            .section    __TEXT,__text,regular,pure_instructions
            .globl  _func
            .align  2
            .code   16
            .thumb_func _func
        _func:
            push    {r4, r5, r6, r7, lr}
            add r7, sp, #12
            str r8, [sp, #-4]!
            sub sp, #8
            vmov.f32    s0, #2.000000e+00
            movw    r8, :lower16:(L_.str-(LPC0_0+4))
            vmov    s2, r0
            movt    r8, :upper16:(L_.str-(LPC0_0+4))
            vcvt.f32.s32    d1, d1
        LPC0_0:
            add r8, pc
            movs    r4, #0
            vdiv.f32    s0, s0, s2
            vsqrt.f32   s0, s0
            vcvt.f64.f32    d16, s0
            vmov    r5, r6, d16
        LBB0_1:
            mov r1, r4
            mov r0, r8
            mov r2, r5
            mov r3, r6
            vstr.64 d16, [sp]
            adds    r4, #1
            blx _printf
            cmp r4, #5
            bne LBB0_1
            movs    r0, #0
            add sp, #8
            ldr r8, [sp], #4
            pop {r4, r5, r6, r7, pc}
    
            .globl  _main
            .align  2
            .code   16
            .thumb_func _main
        _main:
            push    {r7, lr}
            mov r7, sp
            movs    r0, #8
            bl  _func
            movs    r0, #0
            pop {r7, pc}
    
            .section    __TEXT,__cstring,cstring_literals
        L_.str:
            .asciz   "m[%d]: %f, v: %f\n"
    
    
        .subsections_via_symbols
    
    1. 汇编前面的代码,将数组'm [5]'声明为'double m [5]'
    2.         .section    __TEXT,__text,regular,pure_instructions
              .section    __TEXT,__textcoal_nt,coalesced,pure_instructions
              .section    __TEXT,__const_coal,coalesced
              .section    __TEXT,__picsymbolstub4,symbol_stubs,none,16
              .section    __TEXT,__StaticInit,regular,pure_instructions
              .syntax unified
              .section    __TEXT,__text,regular,pure_instructions
              .globl  _func
              .align  2
              .code   16
              .thumb_func _func
          _func:
              push    {r4, r5, r6, r7, lr}
              add r7, sp, #12
              str r8, [sp, #-4]!
              **vpush {d8}**
              sub sp, #8
              vmov.f32    s0, #2.000000e+00
              movw    r8, :lower16:(L_.str-(LPC0_0+4))
              vmov    s2, r0
              movt    r8, :upper16:(L_.str-(LPC0_0+4))
              vcvt.f32.s32    d1, d1
          LPC0_0:
              add r8, pc
              movs    r4, #0
              vdiv.f32    s0, s0, s2
              vcvt.f64.f32    d16, s0
              vsqrt.f64   d8, d16
              vmov    r5, r6, d8
          LBB0_1:
              mov r1, r4
              mov r0, r8
              mov r2, r5
              mov r3, r6
              vstr.64 d8, [sp]
              adds    r4, #1
              blx _printf
              cmp r4, #5
              bne LBB0_1
              movs    r0, #0
              add sp, #8
              vpop    {d8}
              ldr r8, [sp], #4
              pop {r4, r5, r6, r7, pc}
      
              .globl  _main
              .align  2
              .code   16
              .thumb_func _main
          _main:
              push    {r7, lr}
              mov r7, sp
              movs    r0, #8
              bl  _func
              movs    r0, #0
              pop {r7, pc}
      
              .section    __TEXT,__cstring,cstring_literals
          L_.str:
              .asciz   "m[%d]: %f, v: %f\n"
      
      
          .subsections_via_symbols
      

1 个答案:

答案 0 :(得分:1)

目前尚不清楚哪个程序集出错,因为它们都标记为'将数组m[5]声明为double m[5]',遗憾的是我没有硬件或交叉编译器来重现您的问题

值得注意的是,两个汇编代码中的循环非常相似。唯一的区别是v位于第一个d16和第二个d8。传递给v的{​​{1}}位于printf的两个循环中,并在调用(r5,r6)之前正确复制到(r2,r3)。对于可变函数,与非可变函数相反,浮点寄存器不应用于传递参数。因此两个循环看起来都是正确的。

我能想到的唯一解释是用于编译代码的ABI与包含printf的库的ABI不匹配。特别是考虑到编译后的代码来自交叉编译器,我假设printf来自系统上的动态库。由于printf被称为符合ARM的EABI,我认为该错误位于库的printf

如果您的交叉编译器允许静态链接,您可以尝试这样做,因为您将使用与编译器对应的库。当然应用程序变得更大,但它至少可以证实对printf的实现的怀疑。您可能想要检查库是否使用符合EABI的编译器进行编译。如果您可以在iPad上的调试器上单步执行printf,那么您应该能够确定printf从哪里获取其浮点参数。它应该从printf开始。

不幸的是,我不能给出一个确凿的答案,但我希望我的进一步调查指示是有帮助的。