Question

当用户点击closeShareView时，我不希望contentView被调用，仅在modalView上，我该怎么做？

UIWindow* mainWindow = (((AppDelegate *)[UIApplication sharedApplication].delegate).window);

// Modal view
UIView *modalView = [[UIView alloc] initWithFrame:[[UIScreen mainScreen] bounds]];
modalView.backgroundColor = [[UIColor blackColor] colorWithAlphaComponent:0.8f];

// Content view (goes inside modalView)
UIView *contentView = [[UIView alloc] initWithFrame:CGRectMake(modalView.center.x, modalView.center.y, 220, 220)];
[modalView addSubview:contentView];
[mainWindow addSubview:modalView];

// Tap gesture (added to modalView)
UITapGestureRecognizer *gr = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(closeShareView:)];
gr.numberOfTapsRequired = 1;
[modalView addGestureRecognizer:gr];

Answer 1

首先，遵循头文件中的UIGestureRecognizerDelegate协议。

将UIGestureRecognizer的代理设置为self。

然后设置子视图的标记，例如到100（但你应该使用常数）。

然后使用类似的东西：

- (BOOL)gestureRecognizerShouldBegin:(UIGestureRecognizer *)gestureRecognizer
{
    CGPoint point = [gestureRecognizer locationInView:self.view];
    UIView *viewTouched = [self.view hitTest:point withEvent:nil];
    if (viewTouched.tag == 100) {
        // Don't BEGIN the gestureRecognizer
        return NO;
    } else {
        // Do BEGIN the gestureRecognizer
        return YES;
    }
}

Answer 2

所以你想要一些像“在内容视图外点击以解除模态”这样的交易？

不是将水龙头手势添加到整个模态视图，而是有一个处理它的背景视图，内容视图会自然拦截所有水龙头（如果它启用了用户交互），所以你基本上不必做任何编码。

UIWindow* mainWindow = (((AppDelegate *)[UIApplication sharedApplication].delegate).window);

// Modal view
UIView *modalView = [[UIView alloc] initWithFrame:[[UIScreen mainScreen] bounds]];

// Background tap view
UIView *backgroundView = [[UIView alloc] initWithFrame:modalView.bounds];
backgroundView.backgroundColor = [UIColor colorWithWhite:0.0 alpha:0.8];
[modalView addSubview:backgroundView];

// Content view (goes inside modalView)
UIView *contentView = [[UIView alloc] initWithFrame:CGRectMake(modalView.center.x, modalView.center.y, 220, 220)];
[modalView addSubview:contentView];
[mainWindow addSubview:modalView];

// Tap gesture (added to backgroundView)
UITapGestureRecognizer *gr = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(closeShareView:)];
gr.numberOfTapsRequired = 1;
[backgroundView addGestureRecognizer:gr];

Answer 3

我只是检查被触摸的视图是否是自我，否则它是一个子视图，手势不应该开始：

func gestureRecognizerShouldBegin(gestureRecognizer: UIGestureRecognizer) -> Bool {
    let point = gestureRecognizer.locationInView(self.view)
    if let viewTouched = self.view.hitTest(point, withEvent: nil) where viewTouched != self.view {
        return false
    } else {
        return true
    }
}

Answer 4

  @objc func handleTap(_ sender: UITapGestureRecognizer){
    let point = sender.location(in: subview)
    if !(tapView.frame.contains(point)) {
        self.dismiss(animated: true, completion: nil)
    }

}

在这里，tapview是添加了轻击手势的视图，子视图是其子视图

Answer 5

我上面有一个 backgroundView 和一个 tableView：

let tapGestureRecognizer = UITapGestureRecognizer(target: self, action: #selector(backgroundTapped))
tapGestureRecognizer.delegate = self
backgroundView.addGestureRecognizer(tapGestureRecognizer)



// MARK: - UIGestureRecognizerDelegate

extension PhoneListViewController: UIGestureRecognizerDelegate {
    func gestureRecognizerShouldBegin(_ gestureRecognizer: UIGestureRecognizer) -> Bool {
        let point = gestureRecognizer.location(in: self.tableView)
        return !self.tableView.point(inside: point, with: nil)
    }
}

防止子视图上的UITapGestureRecognizer

5 个答案: