Laravel 4无法运行整个RAW查询

时间:2013-07-13 13:08:05

标签: php mysql laravel laravel-4

我想使用laravel的DB类来执行mysql查询,但是Laravel提供的所有函数都没有工作。

这些都不起作用:DB :: statment()/ DB :: select()/ DB :: raw()/ DB :: update()/ DB :: select(DB :: raw())< / p>

以下是我想查询的代码:

DROP TABLE users;

CREATE TABLE `users` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `u_username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_email` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_regdate` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `u_birthday` date NOT NULL DEFAULT '0000-00-00',
  `u_lastlogin` int(11) NOT NULL,
  `u_logcout` int(11) NOT NULL DEFAULT '0',
  `u_level` tinyint(1) NOT NULL DEFAULT '0',
  `u_language` tinyint(1) NOT NULL DEFAULT '0',
  `u_status` tinyint(1) NOT NULL DEFAULT '0',
  `u_gender` tinyint(1) NOT NULL DEFAULT '0',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

INSERT INTO users VALUES("1","admin","admin@example.com","$2y$08$9sBJh7iyF9Yr6xvsieNmBOsotGPBkZFydVjb/Yk5Fzh4IGBVo7Je6","0000-00-00 00:00:00","0000-00-00","0","0","9","0","0","0");
INSERT INTO users VALUES("2","moderator","mod@example.com","$2y$08$15/tIKPM/8gATSzkmey5tuAA/PL4lJeFq7liTETyz0h1dkOotwp3G","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");
INSERT INTO users VALUES("3","helper","help@example.com","$2y$08$nTtZU9/UBeRLbYJRO/XwCe2D/B57ofx2bCN8vGEiHkqO.bPra0WT6","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");
INSERT INTO users VALUES("4","dude12","dude@example.com","$2y$08$y0JweKtWxJFRF7Ko8q0zkODY.EWEKJ.CR1dDco6aCJh8ssKdzQ6RC","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");
INSERT INTO users VALUES("5","girl1","girl@example.com","$2y$08$UKjJzxDuYW7upqeLsm1VOOo2jUoqMaai0/1jFxvLDzC6eWjin3yOe","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0");

我已经查看并尝试了这两个主题的方法,但没有任何工作:

cannot-run-raw-query-in-laravel-4

laravel-4-how-to-run-a-raw-sql

使用“DB :: select(DB :: raw($ query))”或DB :: statement执行时返回错误:

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CREATE TABLE `users` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `u_use' at line 3 (SQL: DROP TABLE users; CREATE TABLE `users` ( `id` int(10) unsigned NOT NULL AUTO_INCREMENT, `u_username` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `u_email` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL, `u_regdate` datetime NOT NULL DEFAULT '0000-00-00 00:00:00', `u_birthday` date NOT NULL DEFAULT '0000-00-00', `u_lastlogin` int(11) NOT NULL, `u_logcout` int(11) NOT NULL DEFAULT '0', `u_level` tinyint(1) NOT NULL DEFAULT '0', `u_language` tinyint(1) NOT NULL DEFAULT '0', `u_status` tinyint(1) NOT NULL DEFAULT '0', `u_gender` tinyint(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; INSERT INTO users VALUES("1","admin","admin@example.com","$2y$08$9sBJh7iyF9Yr6xvsieNmBOsotGPBkZFydVjb/Yk5Fzh4IGBVo7Je6","0000-00-00 00:00:00","0000-00-00","0","0","9","0","0","0"); INSERT INTO users VALUES("2","moderator","mod@example.com","$2y$08$15/tIKPM/8gATSzkmey5tuAA/PL4lJeFq7liTETyz0h1dkOotwp3G","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); INSERT INTO users VALUES("3","helper","help@example.com","$2y$08$nTtZU9/UBeRLbYJRO/XwCe2D/B57ofx2bCN8vGEiHkqO.bPra0WT6","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); INSERT INTO users VALUES("4","dude12","dude@example.com","$2y$08$y0JweKtWxJFRF7Ko8q0zkODY.EWEKJ.CR1dDco6aCJh8ssKdzQ6RC","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); INSERT INTO users VALUES("5","girl1","girl@example.com","$2y$08$UKjJzxDuYW7upqeLsm1VOOo2jUoqMaai0/1jFxvLDzC6eWjin3yOe","0000-00-00 00:00:00","0000-00-00","0","0","0","0","0","0"); ) (Bindings: array ( ))

3 个答案:

答案 0 :(得分:25)

执行SQL代码就像我在问题中提供的那样,可以使用

执行
DB::unprepared( $code );

我希望这能帮助那些遇到同样问题的人:D

Answer found while looking through laravel issues

答案 1 :(得分:2)

从数据库中删除users表,然后尝试这个并让我知道它是否有效:

DB::insert('CREATE TABLE `users` (
  `id` int(10) unsigned NOT NULL AUTO_INCREMENT,
  `u_username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_email` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `password` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `u_regdate` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
  `u_birthday` date NOT NULL DEFAULT '0000-00-00',
  `u_lastlogin` int(11) NOT NULL,
  `u_logcout` int(11) NOT NULL DEFAULT '0',
  `u_level` tinyint(1) NOT NULL DEFAULT '0',
  `u_language` tinyint(1) NOT NULL DEFAULT '0',
  `u_status` tinyint(1) NOT NULL DEFAULT '0',
  `u_gender` tinyint(1) NOT NULL DEFAULT '0',
  PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci');

//and so on for all the other queries.

答案 2 :(得分:2)

这段代码怎么样? 我发现使用migrations & db seeding非常有用 - 特别是对于部署。

Schema::create('users', function($table){
    $table->increments('id');
    $table->string('u_username');
    $table->string('u_email');
    $table->string('password');
    $table->datetime('u_regdate');
    $table->date('u_birthday');
    $table->integer('u_lastlogin');
    $table->integer('u_logcout')->default(0);
    $table->tinyinteger('u_level')->default(0);
    $table->tinyinteger('u_language')->default(0);
    $table->tinyinteger('u_status')->default(0);
    $table->tinyinteger('u_gender')->default(0);
});


// Repeat this for other users as well
User::create([
    'u_username' =>     'admin',
    'u_email' =>        'admin@example.com',
    'password' =>       Hash::make('users-password'),
    'u_regdate' =>      date('Y-m-d H:i:s'),
    'u_birthday' =>     '1980-01-01',
    'u_lastlogin' =>    0,
    'u_logcout' =>      0,
    'u_level' =>        9,
    'u_language' =>     0,
    'u_status' =>       0,
    'u_gender' =>       0,
]);