Question

我正在通过网络创建一个多人游戏，所以我必须对网络事件做出反应。

我有这个简单的代码，但removePlayer方法不起作用。 addPlayer（）工作正常。

<table id="userlist2" class="tablesorter" cellspacing="0">
    <thead>
        <tr>
            <th>Name</th>
            <th>Queue</th>
            <th>Points</th>
        </tr>
    </thead>
    <tbody data-bind="foreach: players">
        <tr>
            <td data-bind="text: name"></td>
            <td data-bind="text: queue"></td>
            <td data-bind="text: score"></td>
        </tr>
    </tbody>
</table>


function PlayerViewModel() {
    var self = this;
    self.players = ko.observableArray();

    self.addPlayer = function (Name, QueuePos, Score) {
        self.players.push({
            name: Name,
            queue: QueuePos,
            score: Score
        });
    }


    self.removePlayer = function (Name) {
        for (var i = 0; i < self.players().length; i++) {

            if (self.players()[i].name == Name) console.log(i);
            self.players().splice(i, 1);
        }
    }
}


players = new PlayerViewModel();
ko.applyBindings(players);

players.addPlayer('Player1', '0', '0');
players.addPlayer('Player2', '0', '0');
players.removePlayer('Player2');

继承人http://jsfiddle.net/xseTc/

Answer 1

您必须使用remove function：

self.removePlayer = function (Name) {
    self.players.remove(function(player) {
        return player.name == Name;
    });

}

See fiddle

<强> HTML

<table id="userlist2" class="tablesorter" cellspacing="0">
    <thead>
        <tr>
            <th>Name</th>
            <th>Queue</th>
            <th>Points</th>
        </tr>
    </thead>
    <tbody data-bind="foreach: players">
        <tr>
            <td data-bind="text: name"></td>
            <td data-bind="text: queue"></td>
            <td data-bind="text: score"></td>
        </tr>
    </tbody>
</table>

<强>的javascript

function PlayerViewModel() {
    var self = this;

    self.players = ko.observableArray();  

    self.addPlayer = function (Name, QueuePos, Score) {
        self.players.push({
            name: Name,
            queue: QueuePos,
            score: Score
        });
    }

    self.removePlayer = function (Name) {
        self.players.remove(function(player) {
            return player.name == Name;
        });
    }
}

players = new PlayerViewModel();
ko.applyBindings(players);

players.addPlayer('Player1', '0', '0');
players.addPlayer('Player2', '0', '0');
players.removePlayer('Player2', '0', '0');

Answer 2

工作删除功能：

self.removePlayer = function (name) {
    self.players.remove(function(player) { 
        return player.name == name
    });
}

Answer 3

你的代码很好，除了你有2个错误：

if (self.players()[i].name == Name) console.log(i);
    self.players().splice(i, 1);

首先在这里你执行2行所以要执行它们你需要使用{}所以用以下代码替换它：

if (self.players()[i].name == Name) {
    console.log(i);
    self.players.splice(i, 1);
}

第二次使用splice您需要使用()调用您的可观察数组，以便按以下方式使用它：

self.players.splice(i, 1);

<强> Working Demo

Answer 4

如果您将视图模型添加到这样的玩家数组中：

self.addPlayer = function (Name, QueuePos, Score) {
    self.players.push(new PlayerVM(Name, QueuePos, Score)));
}

然后您可以像这样删除播放器对象：

self.removePlayer = function (player) {
    self.players.remove(player);
}

或者在播放器vm中：

parentVM.players.remove(self);

Answer 5

根据淘汰网站的最佳信息来源：https://knockoutjs.com/documentation/observableArrays.html

您可以直接使用remove方法- self.players.remove（self.players（）[i]）;

从Knockout.JS中的数组中删除特定元素

5 个答案: