我有一个程序,多个客户端可以使用套接字连接到服务器。
private void performConnect()
{
while (true)
{
if (myList.Pending())
{
thrd = thrd + 1;
tcpClient = myList.AcceptTcpClient();
IPEndPoint ipEndPoint = (IPEndPoint)tcpClient.Client.RemoteEndPoint;
string clientIP = ipEndPoint.Address.ToString();
nStream[thrd] = tcpClient.GetStream();
currentMsg = "\n New IP client found :" + clientIP;
recieve[thrd].Start();
this.Invoke(new rcvData(addNotification));
try
{
addToIPList(clientIP);
}
catch (InvalidOperationException exp)
{
Console.Error.WriteLine(exp.Message);
}
Thread.Sleep(1000);
}
}
}
然后,服务器可以使用此代码将数据(聊天消息)发送到选定的客户端。
private void sendData(String data)
{
IPAddress ipep =IPAddress.Parse(comboBox1.SelectedItem.ToString());
Socket server = new Socket(AddressFamily.InterNetwork , SocketType.Stream, ProtocolType.Tcp);
IPEndPoint ipept = new IPEndPoint( ipep, hostPort);
NetworkStream nStream = tcpClient.GetStream();
ASCIIEncoding asciidata = new ASCIIEncoding();
byte[] buffer = asciidata.GetBytes(data);
if (nStream.CanWrite)
{
nStream.Write(buffer, 0, buffer.Length);
nStream.Flush();
}
}
问题是,无论我从组合框中选择什么IP,我发送的消息将始终被定向/发送到连接到服务器的最后一个IP ..请有人帮我找到错误..所有帮助都将是感谢,提前谢谢!
答案 0 :(得分:1)
那是因为你在sendData
执行了
NetworkStream nStream = tcpClient.GetStream();
其中tcpClient
变量存储最后接受的连接。除此之外,您应该使用存储所有连接流的nStream[]
数组。