Question

我收到以下错误：The active result for the query contains no fields

以下是我的代码

<?php
session_start();
include 'dbconnect_three.php';
include 'dbconnect.php';
include 'dbconnect_two.php';

$uname      = $_SESSION['user'];
$email      = $_SESSION['email'];
$message_id = $_POST['mess_id'];
$maxseq     = $_POST['maxseq'];
$otheruser  = $_POST['otheruser'];

//The part below is the one that does the query to retrieve the messages from the database

$sql_message_retriver         = "SELECT message FROM inbox WHERE message_id='$message_id' ";
$sql_message_retriever_result = sqlsrv_query($conn_three, $sql_message_retriever);


while ($sql_message_result_display = SQLSRV_FETCH_ARRAY($sql_message_retriever_result, SQLSRV_FETCH_ASSOC)) {
    $message_string = $sql_message_result_display['message'];
    echo "<right>$message_string</right>";
}

$seen   = 2;
$maxseq = $maxseq + 1;

echo "<form action=// method=post>";
echo "Messageinput type=text name=update>";
echo "<input type=hidden name=message_id value=$message_id>"; // gotta fix this part
echo "<input type=hidden name=maxseq value=$maxseq>";
echo "<input type=hidden name=otheruser value=$otheruser>";
echo "<input type=hidden name=otheremail value=$otheremail>";
echo "<input type=hidden name=keyes value=$keyes>";
echo "<input type=submit name=submit value=Reply>";
echo "</form>";

print_r(sqlsrv_errors());

?>

我得到的确切错误：

Array (
    [0] => Array (
        [0] => IMSSP
        [SQLSTATE] => IMSSP
        [1] => -28
        [code] => -28
        [2] => The active result for the query contains no fields.
        [message] => The active result for the query contains no fields.
    )
)

以下是我发现从其他论坛解决问题的一个建议：使用sqlsrv_next_result。我使用它，它说ODBC函数序列错误（类似的东西）。

当我更改我的sql语句时，请注意以下内容：

$sql_id_two="SELECT message 
             FROM   inbox 
             WHERE  message_id = '$message_id' 
                    AND to_email = '$email' 
                     OR from_email = '$email'";

它实际上有效并显示消息。这很奇怪。

任何人都可以解释此错误消息吗？

Answer 1

我发现什么是错的，我的sql语句出现了拼写错误。所以我为sqlsrv_query插入了错误的资源2拼写。我怎么能这么傻。

Answer 2

在我的情况下，using PDO，我不得不拨打nextRowset()，因为我试图在insert之前阅读select的结果中的列。

SQLSRV equivalent是：

mixed sqlsrv_next_result ( resource $stmt )

查询的活动结果不包含任何字段

2 个答案: