Question

我要创建一个tkinter gui应用程序，我知道我希望它看起来如何。但在使用tkinter后，我发现当你按下底部的按钮时，无法在屏幕之间切换。我知道它什么都不做，但下面是我想要的简单布局，并在“myframe1”和“myframe2”之间切换，就像Apple App Store布局一样。这有可能吗？

from tkinter import *

tk = Tk()
tk.geometry("300x300")

myframe1 = Frame(tk,background="green",width=300,height=275)
myframe1.pack()

myframe2 = Frame(tk,background="cyan",width=300,height=275)
myframe2.pack()

btnframe = Frame(tk)

btn1 = Button(btnframe,text="screen1",width=9)
btn1.pack(side=LEFT)

btn2 = Button(btnframe,text="screen2",width=9)
btn2.pack(side=LEFT)

btn3 = Button(btnframe,text="screen3",width=9)
btn3.pack(side=LEFT)

btn4 = Button(btnframe,text="screen4",width=9)
btn4.pack(side=LEFT)

myframe1.pack()
btnframe.pack()

tk.mainloop()

Answer 1

你在寻找像标签小部件这样的东西吗？您可以按建议here

使用forget和pack

这是我在我的代码中使用的类：

class MultiPanel():
  """We want to setup a pseudo tabbed widget with three treeviews. One showing the disk, one the pile and
  the third the search results. All three treeviews should be hooked up to exactly the same event handlers
  but only one of them should be visible at any time.
  Based off http://code.activestate.com/recipes/188537/
  """
  def __init__(self, parent):
    #This is the frame that we display
    self.fr = tki.Frame(parent, bg='black')
    self.fr.pack(side='top', expand=True, fill='both')
    self.widget_list = []
    self.active_widget = None #Is an integer

  def __call__(self):
    """This returns a reference to the frame, which can be used as a parent for the widgets you push in."""
    return self.fr

  def add_widget(self, wd):
    if wd not in self.widget_list:
      self.widget_list.append(wd)
    if self.active_widget is None:
      self.set_active_widget(0)
    return len(self.widget_list) - 1 #Return the index of this widget

  def set_active_widget(self, wdn):
    if wdn >= len(self.widget_list) or wdn < 0:
      logger.error('Widget index out of range')
      return
    if self.widget_list[wdn] == self.active_widget: return
    if self.active_widget is not None: self.active_widget.forget()
    self.widget_list[wdn].pack(fill='both', expand=True)
    self.active_widget = self.widget_list[wdn]

Answer 2

开始使用的东西：

def toggle(fshow,fhide):
    fhide.pack_forget()
    fshow.pack()


btn1 = Button(btnframe,text="screen1", command=lambda:toggle(myframe1,myframe2),width=9)
btn1.pack(side=LEFT)

btn2 = Button(btnframe,text="screen2",command=lambda:toggle(myframe2,myframe1),width=9)
btn2.pack(side=LEFT)

是否有可能在tkinter中拉出同一位置的不同屏幕

2 个答案: