使用Python正则表达式逐行划分

Question

我有一个字符串：

"""Hello. It's good to meet you.
My name is Bob."""

我正在尝试找到将其拆分为按句点和换行符划分的列表的最佳方法：

["Hello", "It's good to meet you", "My name is Bob"]

我很确定我应该使用正则表达式，但是，由于没有经验，我很难弄清楚如何做到这一点。

Answer 1

您不需要正则表达式。

>>> txt = """Hello. It's good to meet you.
... My name is Bob."""
>>> txt.split('.')
['Hello', " It's good to meet you", '\nMy name is Bob', '']
>>> [x for x in map(str.strip, txt.split('.')) if x]
['Hello', "It's good to meet you", 'My name is Bob']

Answer 2

对于您的示例，分割点，可选地后跟空格（并忽略空结果）就足够了：

>>> s = """Hello. It's good to meet you.
... My name is Bob."""
>>> import re
>>> re.split(r"\.\s*", s)
['Hello', "It's good to meet you", 'My name is Bob', '']

在现实生活中，你必须处理Mr. Orange，Dr. Greene和George W. Bush，但是......

Answer 3

>>> s = """Hello. It's good to meet you.
... My name is Bob."""
>>> import re
>>> p = re.compile(r'[^\s\.][^\.\n]+')
>>> p.findall(s)
['Hello', "It's good to meet you", 'My name is Bob']
>>> s = "Hello. #It's good to meet you # .'"
>>> p.findall(s)
['Hello', "#It's good to meet you # "]

Answer 4

您可以使用此拆分

re.split(r"(?<!^)\s*[.\n]+\s*(?!$)", s)

Answer 5

矿：

re.findall('(?=\S)[^.\n]+(?<=\S)',su)