如何在C中初始化这个嵌套结构?
typedef struct _s0 {
int size;
double * elems;
}StructInner ;
typedef struct _s1 {
StructInner a, b, c, d, e;
long f;
char[16] s;
}StructOuter; StructOuter myvar = {/* what ? */ };
答案 0 :(得分:14)
将所有内容初始化为0(正确类型)
StructOuter myvar = {0};
将成员初始化为特定值
StructOuter myvar = {{0, NULL}, {0, NULL}, {0, NULL},
{0, NULL}, {0, NULL}, 42.0, "foo"};
/* that's {a, b, c, d, e, f, s} */
/* where each of a, b, c, d, e is {size, elems} */
修改的
如果您有C99编译器,您也可以使用“指定的初始值设定项”,如:
StructOuter myvar = {.c = {1000, NULL}, .f = 42.0, .s = "foo"};
/* c, f, and s initialized to specific values */
/* a, b, d, and e will be initialized to 0 (of the right kind) */
答案 1 :(得分:2)
double a[] = { 1.0, 2.0 };
double b[] = { 1.0, 2.0, 3.0 };
StructOuter myvar = { { 2, a }, { 3, b }, { 2, a }, { 3, b }, { 2, a }, 1, "a" };
似乎a和b不能在普通C中就地初始化
答案 2 :(得分:1)
特别突出显示结构标签:
StructInner a = {
.size: 1,
.elems: { 1.0, 2.0 }, /* optional comma */
};
StructOuter b = {
.a = a, /* struct labels start with a dot */
.b = a,
a, /* they are optional and you can mix-and-match */
a,
.e = { /* nested struct initialization */
.size: 1,
.elems: a.elems
},
.f = 1.0,
.s = "Hello", /* optional comma */
};
答案 3 :(得分:0)
以下内容也适用于GCC,C99。海湾合作委员会没有抱怨。我不确定这是否标准。
double arr[] = { 1.0, 2.0 }; // should be static or global
StructOuter myvar =
{
.f = 42,
.s = "foo",
.a.size = 2,
.a.elems = &arr,
.b.size = 0, // you can explicitly show that it is zero
// missing members will actually be initialized to zero
};